题目内容
解下列方程组.(每小题5分,共30分)
(1)
(2) 
(3)
(4) 
(5)
(6) 
(1)
(3)
(5)
(1)
(2)
(3)
(4)
(5)
(6)
(1) 解:将②代入①得


···································· 2分
将
代入②得
························· 4分
∴
是原方程组的解··························· 5分
(2) 解:①+②得
···································· 2分
将
代入①得

···································· 4分
∴
是原方程组的解··························· 5分
(3) 解:②-①得

···································· 2分
将
代入①得


∴
是原方程组的解··························· 5分
(4) 解:原方程组变形为
···················· 1分由①得
③
由②得
④
③+④得
x =" 8···························" 3分
将x = 8代入④得 y =" 1····························" 4分
∴
是原方程组的解···························· 5分
(5) 解:由①得
③································ 1分
由②得
④································ 2分
③×2得
⑤
④×3得
⑥
⑤-⑥得
····································· 3分
将y = 1代入④得
····································· 4分
∴
是原方程组的解···························· 5分
(6) 解:①+②得
③·································· 1分
①-②得
④·································· 2分
③+④得
····································· 3分
将
代入③得y =" –" 2 ··························· 4分
∴
是原方程组的解 5分
将
∴
(2) 解:①+②得
将
∴
(3) 解:②-①得
将
∴
|
由②得
③+④得
将x = 8代入④得 y =" 1····························" 4分
∴
(5) 解:由①得
由②得
③×2得
④×3得
⑤-⑥得
将y = 1代入④得
∴
(6) 解:①+②得
①-②得
③+④得
将
∴
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