题目内容
计算
(1)33+(-10)-(-22)
(2)-14-5×(-3×2)2+(-1)2010
(3)(
-
-
)×(-36)÷(-2)
(4)8×(-
)4-
×[2-(-3)2].
(1)33+(-10)-(-22)
(2)-14-5×(-3×2)2+(-1)2010
(3)(
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 12 |
(4)8×(-
| 1 |
| 2 |
| 1 |
| 6 |
分析:(1)首先利用符号法则把式子进行化简,然后把正数与负数分别相加,然后计算减法即可;
(2)首先计算平方,然后计算乘法,最后进行加减匀速即可求解;
(3)首先把除法转化成乘法运算,然后利用分配律即可求解;
(4)首先计算乘方运算,计算括号内的式子,然后计算乘除,最后计算加减即可求解.
(2)首先计算平方,然后计算乘法,最后进行加减匀速即可求解;
(3)首先把除法转化成乘法运算,然后利用分配律即可求解;
(4)首先计算乘方运算,计算括号内的式子,然后计算乘除,最后计算加减即可求解.
解答:解:(1)33+(-10)-(-22)
=33+(-10)+22
=33+22+(-10)
=55+(-10)
=45
(2)-14-5×(-3×2)2+(-1)2010
=-1-5×(-6)2+1
=-1-5×36+1
=0-180
=-180
(3)(
-
-
)×(-36)÷(-2)
=(
-
-
)×(-36)×(-
)
=(
-
-
)×18
=
×18-
×18-
×18
=
-2-
=1
(4)8×(-
)4-
×[2-(-3)2]
=8×
-
×(2-9)
=
-
×(-7)
=
+
=
+
=
=33+(-10)+22
=33+22+(-10)
=55+(-10)
=45
(2)-14-5×(-3×2)2+(-1)2010
=-1-5×(-6)2+1
=-1-5×36+1
=0-180
=-180
(3)(
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 12 |
=(
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 12 |
| 1 |
| 2 |
=(
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 12 |
=
| 1 |
| 4 |
| 1 |
| 9 |
| 1 |
| 12 |
=
| 9 |
| 2 |
| 3 |
| 2 |
=1
(4)8×(-
| 1 |
| 2 |
| 1 |
| 6 |
=8×
| 1 |
| 16 |
| 1 |
| 6 |
=
| 1 |
| 2 |
| 1 |
| 6 |
=
| 1 |
| 2 |
| 7 |
| 6 |
=
| 3 |
| 6 |
| 7 |
| 6 |
=
| 5 |
| 3 |
点评:本题考查了有理数的混合运算,正确确定运算顺序是关键,正确利用运算律可以简化运算过程.
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