题目内容
计算:
(1)-2-3-5
(2)(-2)÷
×(-3)
(3)(
-
-
)×(-60)
(4)-14+8-23÷(-4)×(-7+5)
(5)100-(-3)÷(
)
(6)-11-2×(-33)+(-22)
(7)-32÷[-32-(-2)3].
(1)-2-3-5
(2)(-2)÷
| 1 |
| 3 |
(3)(
| 2 |
| 3 |
| 1 |
| 12 |
| 4 |
| 15 |
(4)-14+8-23÷(-4)×(-7+5)
(5)100-(-3)÷(
| 3 |
| 4 |
(6)-11-2×(-33)+(-22)
(7)-32÷[-32-(-2)3].
(1)-2-3-5
=-(2+3+5)
=-10;
(2)(-2)÷
×(-3)
=-6×(-3)
=18;
(3)(
-
-
)×(-60)
=-
×60+
×60+
×60
=-40+5+16
=-19;
(4)-14+8-23÷(-4)×(-7+5)
=-1+8-8÷(-4)×(-2)
=-1+8-4
=3;
(5)100-(-3)÷(
)
=100+4
=104;
(6)-11-2×(-33)+(-22)
=-11-66-22
=-99;
(7)-32÷[-32-(-2)3]
=-32÷[-9+8]
=-32÷[-1]
=32.
=-(2+3+5)
=-10;
(2)(-2)÷
| 1 |
| 3 |
=-6×(-3)
=18;
(3)(
| 2 |
| 3 |
| 1 |
| 12 |
| 4 |
| 15 |
=-
| 2 |
| 3 |
| 1 |
| 12 |
| 4 |
| 15 |
=-40+5+16
=-19;
(4)-14+8-23÷(-4)×(-7+5)
=-1+8-8÷(-4)×(-2)
=-1+8-4
=3;
(5)100-(-3)÷(
| 3 |
| 4 |
=100+4
=104;
(6)-11-2×(-33)+(-22)
=-11-66-22
=-99;
(7)-32÷[-32-(-2)3]
=-32÷[-9+8]
=-32÷[-1]
=32.
练习册系列答案
相关题目