题目内容
计算:| x-1 |
| x+1 |
| 4x |
| x2+1 |
分析:首先通分,然后再利用同分母的分式加减运算法则求解即可求得答案.
解答:解:
+
,
=
,
=
,
=
.
| x-1 |
| x+1 |
| 4x |
| x2+1 |
=
| (x-1)( x2+1)+4x(x+1) |
| (x+1)(x2+1) |
=
| x3+x-x2-1+4x2+4x |
| (x+1)(x2+1) |
=
| x3+3x2+5x-1 |
| (x+1)(x2+1) |
点评:此题考查了分式的加减运算法则.解题的关键是注意通分,化简.
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