题目内容
(2011•岳池县模拟)化简:(
-
)÷
-
.
| x+2 |
| x-2 |
| x-2 |
| x+2 |
| x |
| x-2 |
| 5x-22 |
| x2-4 |
分析:先通分,再进行约分即可.
解答:解:原式=
•
-
=
-
=
=
.
| 8x |
| (x-2)(x+2) |
| x-2 |
| x |
| 5x-22 |
| x2-4 |
=
| 8x-16 |
| (x+2)(x-2) |
| 5x-22 |
| (x+2)(x-2) |
=
| 3x+6 |
| (x-2)(x+2) |
=
| 3 |
| x-2 |
点评:本题考查了分式的混合运算,解本题的关键是通分与约分.
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