题目内容

化简求值:[(x﹣y)(x+y)﹣(x﹣y)2+2y(x﹣y)]÷(﹣2y),其中x=﹣,y=2.
解:[(x﹣y)(x+y)﹣(x﹣y)2+2y(x﹣y)]÷(﹣2y),
=[x2﹣y2﹣(x2﹣2xy+y2)+2xy﹣2y2]÷(﹣2y),
=(x2﹣y2﹣x2+2xy﹣y2+2xy﹣2y2)÷(﹣2y),
=(4xy﹣4y2)÷(﹣2y),
=﹣2x+2y,
当x=﹣,y=2时,
原式=﹣2x+2y=﹣2×(﹣)+2×2=1+4=5.
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