题目内容
化简求值.
(1)[(x+y)(x-y)-(x-y)2+2y(x-y)]÷(-2y),其中x=-
,y=2.
(2)已知x2-2x-2=0,求(x-1)2+(x+3)(x-3)+(x-3)(x-1)的值.
(1)[(x+y)(x-y)-(x-y)2+2y(x-y)]÷(-2y),其中x=-
| 1 |
| 2 |
(2)已知x2-2x-2=0,求(x-1)2+(x+3)(x-3)+(x-3)(x-1)的值.
(1)原式=(x-y)[(x+y)-(x-y)+2y]÷(-2y)
=2y-2x,
当 x=-
,y=2时,原式=2×2-2×(-
)=5;
(2)原式=x2-2x+1+x2-9+x2-4x+3
=3x2-6x-5,
原式=3(x2-2x)-5
=3×2-5=1.
=2y-2x,
当 x=-
| 1 |
| 2 |
| 1 |
| 2 |
(2)原式=x2-2x+1+x2-9+x2-4x+3
=3x2-6x-5,
原式=3(x2-2x)-5
=3×2-5=1.
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