题目内容
计算:
(1)1
×[3×(-
)2-1]-
×(-2)3
(2)-9÷3+(
-
)×12+32;
(3)(2
-3
+14)÷(1
)×(-1)2n.
(1)1
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 3 |
(2)-9÷3+(
| 1 |
| 2 |
| 2 |
| 3 |
(3)(2
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
分析:(1)首先将括号里面计算合并,进而去括号得出即可;
(2)首先去掉括号以及化简乘方,进而得出答案;
(3)首先将带分数化成假分数,再利用除以一个数等于乘以这个数的倒数,直接去括号得出即可.
(2)首先去掉括号以及化简乘方,进而得出答案;
(3)首先将带分数化成假分数,再利用除以一个数等于乘以这个数的倒数,直接去括号得出即可.
解答:解:(1)1
×[3×(-
)2-1]-
×(-2)3
=
×(3×
-1)-
×(-8)
=
×
+
×8
=
;
(2)-9÷3+(
-
)×12+32
=-3-
×12+9
=4;
(3)(2
-3
+14)÷(1
)×(-1)2n
=(
-
+14)×
×1
=2-3+12
=11.
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 3 |
=
| 3 |
| 2 |
| 4 |
| 9 |
| 1 |
| 3 |
=
| 3 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
=
| 19 |
| 6 |
(2)-9÷3+(
| 1 |
| 2 |
| 2 |
| 3 |
=-3-
| 1 |
| 6 |
=4;
(3)(2
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
=(
| 7 |
| 3 |
| 7 |
| 2 |
| 6 |
| 7 |
=2-3+12
=11.
点评:此题主要考查了有理数的混合运算,熟练掌握运算法则是解题关键.
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