题目内容
观察x+| 1 |
| x |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| x |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| x |
| 1 |
| t |
| 1 |
| t |
| 1 |
| x-1 |
| 1 |
| t-1 |
分析:根据题目条件,总结出规律,然后将x+
=t+
转化为符合规律的形式,直接写出答案即可.
| 1 |
| x-1 |
| 1 |
| t-1 |
解答:解:x+
=t+
可化为(x-1)+
=(t-1)+
,
根据x+
=t+
的解是x1=t,x2=
可得,
x-1=t-1或x-1=
,
即x1=t,x2=
+1=
.
故答案为x1=t,x2=
.
| 1 |
| x-1 |
| 1 |
| t-1 |
| 1 |
| x-1 |
| 1 |
| t-1 |
根据x+
| 1 |
| x |
| 1 |
| t |
| 1 |
| t |
x-1=t-1或x-1=
| 1 |
| t-1 |
即x1=t,x2=
| 1 |
| t-1 |
| t |
| t-1 |
故答案为x1=t,x2=
| t |
| t-1 |
点评:此题考查了分式方程的解,是一道规律性题目.根据条件探索出规律,利用规律探索出答案是解题的关键.
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