题目内容
计算：(
)-1+16÷(-2)3+(2011-
)0-
•tan60°．
| 1 |
| 3 |
| π |
| 3 |
| 3 |
(
)-1+16÷(-2)3+(2011-
)0-
•tan60°
=
+16÷（-8）+1-
×
=3-2+1-3
=-1．
| 1 |
| 3 |
| π |
| 3 |
| 3 |
=
| 1 | ||
|
| 3 |
| 3 |
=3-2+1-3
=-1．
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世纪百通期末金卷系列答案题目内容
| 1 |
| 3 |
| π |
| 3 |
| 3 |
| 1 |
| 3 |
| π |
| 3 |
| 3 |
| 1 | ||
|
| 3 |
| 3 |
世纪百通期末金卷系列答案