题目内容
在实数范围内分解因式:x4-4x2+3=______.
x4-4x2+3=x4-4x2+3+1-1
=(x4-4x2+4)-1
=(x2-2)2-1
=(x2-2+1)(x2-2-1)
=(x2-1)(x2-3)
=(x+1)(x-1)(x+
)(x-
).
=(x4-4x2+4)-1
=(x2-2)2-1
=(x2-2+1)(x2-2-1)
=(x2-1)(x2-3)
=(x+1)(x-1)(x+
| 3 |
| 3 |
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