题目内容
先化简,再求值:(| x-1 |
| x2+x |
| x |
| x2+2x+1 |
| 1 |
| x |
| 3 |
分析:先对x2+x,x2+2x+1分解因式,再通分进行化简求值.
解答:解:原式=[
-
]•x
=
•x
=
,
当x=
-1时,原式=-
.
| x-1 |
| x(x+1) |
| x |
| (x+1)2 |
=
| x2-1-x2 |
| x(x+1)2 |
=
| -1 |
| (x+1)2 |
当x=
| 3 |
| 1 |
| 3 |
点评:本题考查分式的化简求值,把分式化到最简是解答的关键.
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