题目内容
(1)(y-1)2-4=0
(2)(配方法)2x2-5x+2=0.
(2)(配方法)2x2-5x+2=0.
(1)移项得:(y-1)2=4,
开方得:y-1=±2,
解得:y1=3,y2=-1.
(2)x2-
x+1=0,
x2-
x+(
)2=-1+(
)2,
(x-
)2=
,
x-
=±
,
∴x1=
,x2=2.
开方得:y-1=±2,
解得:y1=3,y2=-1.
(2)x2-
| 5 |
| 2 |
x2-
| 5 |
| 2 |
| 5 |
| 4 |
| 5 |
| 4 |
(x-
| 5 |
| 4 |
| 9 |
| 16 |
x-
| 5 |
| 4 |
| 3 |
| 4 |
∴x1=
| 1 |
| 2 |
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