题目内容
(1)计算:
×
÷
+
;
(2)计算:5-
×5
+(2
÷3
)-3(结果可用幂的形式表示)
| 2 |
| 3 |
| 1 | ||
|
(-3)2+(
|
(2)计算:5-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
分析:(1)把除法变成乘法,同时求出被开方里面的,再把能开方得开出来即可.
(2)根据积的乘方的逆运用进行计算,再求出括号内的即可.
(2)根据积的乘方的逆运用进行计算,再求出括号内的即可.
解答:解:(1)原式=
×
×
+
=2
+
=2
+4;
(2)原式=(
)
×5
+[(2÷3)
]-3
=(
×5)
+(
)
×(-3)
=1+(
) -
.
| 2 |
| 3 |
| 2 |
| 9+7 |
=2
| 3 |
| 16 |
=2
| 3 |
(2)原式=(
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
=(
| 1 |
| 5 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
=1+(
| 2 |
| 3 |
| 2 |
| 3 |
点评:本题考查了分数指数和积的乘方和幂的乘方,主要考查学生灵活运用性质进行计算的能力.
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