题目内容
先化简,再求值:
(1)
÷
-
,其中x=2;
(2)
÷
-
,其中x=
.
(1)
| 3x-3 |
| x2-1 |
| 3x |
| x+1 |
| 1 |
| x+1 |
(2)
| x2+2x+1 |
| x+2 |
| x2-1 |
| x-1 |
| 1 |
| x+2 |
| 1 |
| 2 |
分析:(1)、(2)先根据分式混合运算的法则把原式进行化简,再把x的值代入进行计算即可.
解答:解:(1)原式=
•
-
=
•
-
=
-
=
,
当x=2时,原式=
=
;
(2)原式=
•
-
=
-
=
当x=
时,原式=
.
| 3(x-1) |
| (x+1)(x-1) |
| x+1 |
| 3x |
| 1 |
| x+1 |
=
| 3 |
| x+1 |
| x+1 |
| 3x |
| 1 |
| x+1 |
=
| 1 |
| x |
| 1 |
| x+1 |
=
| 1 |
| x(x+1) |
当x=2时,原式=
| 1 |
| 2(2+1) |
| 1 |
| 6 |
(2)原式=
| (x+1)2 |
| x+2 |
| 1 |
| x+1 |
| 1 |
| x+2 |
=
| x+1 |
| x+2 |
| 1 |
| x+2 |
=
| x |
| x+2 |
当x=
| 1 |
| 2 |
| 1 |
| 5 |
点评:本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.
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