题目内容
计算:(1)(-2)+(+5)-(+4)-(-3)-3
(2)-5×(-6)+3×(-8)-(-4)×(-7)
(3)(1-
| 1 |
| 6 |
| 3 |
| 4 |
(4)(-1)10×2+(-2)3÷4.
分析:(1)先化简,再把正数相加,负数相加即可;
(2)先算乘法,再算加减;
(3)运用乘法的分配律进行计算即可;
(4)按运算顺序计算即可.
(2)先算乘法,再算加减;
(3)运用乘法的分配律进行计算即可;
(4)按运算顺序计算即可.
解答:解:(1)原式=-2+5-4+3-3
=(-2-4-3)+(5+3)
=-9+8
=-1;
(2)原式=30-24-28
=30+[(-24)+(-28)]
=30-52
=-(52-30)
=-22;
(3)原式=-48+
×48-
×48
=-48+8-36
=-76;
(4)(-1)10×2+(-2)3÷4
=1×2+(-8)÷4
=2-2=0.
=(-2-4-3)+(5+3)
=-9+8
=-1;
(2)原式=30-24-28
=30+[(-24)+(-28)]
=30-52
=-(52-30)
=-22;
(3)原式=-48+
| 1 |
| 6 |
| 3 |
| 4 |
=-48+8-36
=-76;
(4)(-1)10×2+(-2)3÷4
=1×2+(-8)÷4
=2-2=0.
点评:本题考查了有理数的混合运算,是基础知识要熟练掌握.
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