题目内容
计算:(1)(-3)+(-4)-(+11)-(-9)=
(2)(-7)×(-5)-90÷(-3)=
(3)
| 1 |
| 12 |
| 1 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
(4)-14-(1-0.5)×
| 1 |
| 3 |
分析:按照有理数混合运算的顺序,先乘除后加减,有括号的先算括号里面的,计算过程中注意正负符号的变化.
解答:解:(1)(-3)+(-4)-(+11)-(-9),
=-3-4-11+9,
=-9;
(2)(-7)×(-5)-90÷(-3),
=35+30,
=65;
(3)
÷(1
-
+
),
=
÷
,
=
;
(4)-14-(1-0.5)×
×[2-(-3)2],
=-1-
×
×(-7),
=
.
故答案为:(1)-9,(2)65,(3)
,(4)
.
=-3-4-11+9,
=-9;
(2)(-7)×(-5)-90÷(-3),
=35+30,
=65;
(3)
| 1 |
| 12 |
| 1 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
=
| 1 |
| 12 |
| 17 |
| 12 |
=
| 1 |
| 17 |
(4)-14-(1-0.5)×
| 1 |
| 3 |
=-1-
| 1 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 6 |
故答案为:(1)-9,(2)65,(3)
| 1 |
| 17 |
| 1 |
| 6 |
点评:本题考查的是有理数的运算能力.
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