题目内容
计算
|
| （1）原式=(2-1)(2+1)(2 2 +1)(2 4+1)(2 8+1) =(2 2 -1)(2 2 +1)(2 4+1)(2 8+1) =(2 4-1)(2 4+1)(2 8+1) =(2 8-1)(2 8+1) =216 -1 |
（2）原式=［（a+(b-c)］×［（a-(b-c)］-(b-c)2 =a2-(b-c)2 -(b-c)2 =a2-2(b-c)2 =a2-2(b2-2bc+c 2) =a2-2b2+4bc-2c 2 |
| （3）原式=(100-2)(100+2)-(100-1)2 =1002-4-1002+200-1 =-4+200-1 =195 |
练习册系列答案
相关题目
