题目内容
化简:| x-y |
| x+3y |
| x2-y2 |
| x2+6xy+9y2 |
| 2y |
| x+y |
分析:首先把各个分式的分子分母能分解因式的分解因式,然后把除法运算转化成乘法运算,进行约分,最后进行加减运算.
解答:解:原式=
•
-
=
•
-
=
-
=
=1.
| x-y |
| x+3y |
| x2+6xy+9y2 |
| x2-y2 |
| 2y |
| x+y |
=
| x-y |
| x+3y |
| (x+3y)2 |
| (x+y)(x-y) |
| 2y |
| x+y |
=
| x+3y |
| x+y |
| 2y |
| x+y |
=
| x+y |
| x+y |
点评:本题主要考查分式的混合运算,注意运算顺序,通分、约分是解题的关键.
练习册系列答案
相关题目