题目内容
先化简,再求值.(1)(x-
| x-4 |
| x-3 |
| x2-4 |
| x-3 |
| x2-1 |
| x2-2x+1 |
| x2-2x |
| x-2 |
| 2 |
| 3 |
分析:(1)首先把括号里因式进行通分,然后把除法运算转化成乘法运算,进行约分化简,最后代值计算,
(2)先把分式化简,再把数代入求值.
(2)先把分式化简,再把数代入求值.
解答:解:(1)原式=
•
=
•
=
,
当x=5时,
=
.
(2)原式=
+
•
=
+1=
,
当x=
时,
=-4.
故答案为
、-4.
| x(x-3)-(x-4) |
| x-3 |
| x-3 |
| (x+2)(x-2) |
| (x-2)2 |
| x-3 |
| x-3 |
| (x+2)(x-2) |
| x-2 |
| x+2 |
当x=5时,
| x-2 |
| x+2 |
| 3 |
| 7 |
(2)原式=
| (x+1)(x-1) |
| (x-1)2 |
| x(x-2) |
| x-2 |
| 1 |
| x |
| x+1 |
| x-1 |
| 2x |
| x-1 |
当x=
| 2 |
| 3 |
| 2x |
| x-1 |
故答案为
| 3 |
| 7 |
点评:分式的混合运算需特别注意运算顺序及符号的处理,也需要对通分、分解因式、约分等知识点熟练掌握.
练习册系列答案
相关题目