题目内容
分解因式:x2-9=______;x2-x+
=______;a3-a=______.
| 1 |
| 4 |
x2-9=(x+3)(x-3);
x2-x+
=(x+
)2;
a3-a
=a(a2-1)
=a(a+1)(a-1).
故答案是:(x+3)(x-3);(x+
)2;a(a+1)(a-1).
x2-x+
| 1 |
| 4 |
| 1 |
| 2 |
a3-a
=a(a2-1)
=a(a+1)(a-1).
故答案是:(x+3)(x-3);(x+
| 1 |
| 2 |
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