题目内容
计算:
(1)(-7)+(-3)+(+9)+(-1);
(2)(-5)-(-7);
(3)
-
-
+
;
(4)(-2
)×(-
)÷(-3
);
(5)
×6
-(-
)÷(-1
)+(0.5)2;
(6)-(-3)2+(-3)2-(-1)3×(
-
)÷
-|-5|.
(1)(-7)+(-3)+(+9)+(-1);
(2)(-5)-(-7);
(3)
| 1 |
| 3 |
| 1 |
| 2 |
| 3 |
| 4 |
| 2 |
| 3 |
(4)(-2
| 2 |
| 5 |
| 3 |
| 4 |
| 3 |
| 5 |
(5)
| 8 |
| 81 |
| 3 |
| 4 |
| 2 |
| 7 |
| 5 |
| 7 |
(6)-(-3)2+(-3)2-(-1)3×(
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 6 |
分析:(1)先去括号,再先把-3与-7相加,然后进行加减运算;
(2)先去括号,再进行减法运算;
(3)先交换得到原式=
+
-
-
,然后进行同分母的加法运算;
(4)先把带分数化为假分数以及除法转化为乘法,然后进行约分即可;
(5)先把带分数化为假分数以及除法转化为乘法得到原式=
×
-(-
)×(-
)+(
)2,再约分,然后通分进行计算;
(6)先进行乘方运算得到原式=-9+9-(-1)×(-
)×6-5,再进行乘法运算,然后进行加减运算.
(2)先去括号,再进行减法运算;
(3)先交换得到原式=
| 1 |
| 3 |
| 2 |
| 3 |
| 2 |
| 4 |
| 3 |
| 4 |
(4)先把带分数化为假分数以及除法转化为乘法,然后进行约分即可;
(5)先把带分数化为假分数以及除法转化为乘法得到原式=
| 8 |
| 81 |
| 27 |
| 4 |
| 2 |
| 7 |
| 7 |
| 12 |
| 1 |
| 2 |
(6)先进行乘方运算得到原式=-9+9-(-1)×(-
| 1 |
| 6 |
解答:解:(1)原式=-7-3+9-1
=-10+9-1
=-1-1
=-2;
(2)原式=-5+7
=2;
(3)原式=
+
-
-
=1-
=-
;
(4)原式=-
×(-
)×(-
)
=-
;
(5)原式=
×
-(-
)×(-
)+(
)2
=
-
+
=
-
+
=
=
;
(6)原式=-9+9-(-1)×(-
)×6-5
=-9+9-1-5
=-6.
=-10+9-1
=-1-1
=-2;
(2)原式=-5+7
=2;
(3)原式=
| 1 |
| 3 |
| 2 |
| 3 |
| 2 |
| 4 |
| 3 |
| 4 |
=1-
| 5 |
| 4 |
=-
| 1 |
| 4 |
(4)原式=-
| 12 |
| 5 |
| 3 |
| 4 |
| 5 |
| 18 |
=-
| 1 |
| 2 |
(5)原式=
| 8 |
| 81 |
| 27 |
| 4 |
| 2 |
| 7 |
| 7 |
| 12 |
| 1 |
| 2 |
=
| 2 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
=
| 8 |
| 12 |
| 2 |
| 12 |
| 3 |
| 12 |
=
| 9 |
| 12 |
=
| 3 |
| 4 |
(6)原式=-9+9-(-1)×(-
| 1 |
| 6 |
=-9+9-1-5
=-6.
点评:本题考查了有理数的运算:先算乘方,再算乘除,然后进行加减运算;有括号先算括号.
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