题目内容
已知
-
=2,则
=
| 1 |
| x |
| 1 |
| y |
| x-4xy-y |
| 2y+xy-2x |
-
| 6 |
| 5 |
-
.| 6 |
| 5 |
分析:先根据题意得出x-y=-2xy,再代入所求代数式进行计算即可.
解答:解:∵
-
=2,
∴
=2,即x-y=-2xy,
原式=
=
=
=-
.
故答案为:-
.
| 1 |
| x |
| 1 |
| y |
∴
| y-x |
| xy |
原式=
| (x-y)-4xy |
| -2(x-y)+xy |
=
| -2xy-4xy |
| (-2)×(-2xy)+xy |
=
| -6xy |
| 5xy |
=-
| 6 |
| 5 |
故答案为:-
| 6 |
| 5 |
点评:本题考查的是分式的化简求值,在解答此类题目时要注意通分及约分的灵活应用.
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