题目内容
先化简,再求值(| x+2 |
| x2-2x |
| x-1 |
| x2-4x+4 |
| x-4 |
| x |
| 3 |
分析:把分式化简,然后把x的值代入化简后的式子求值就可以了.
解答:解:原式=(
-
)×
=
×
=
,
当x=2+
时,原式=
=
.
故答案为
.
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x |
| x-4 |
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
| 1 |
| (x-2)2 |
当x=2+
| 3 |
| 1 | ||
(2+
|
| 1 |
| 3 |
故答案为
| 1 |
| 3 |
点评:本题主要考查分式的化简求值,通分约分是解题的关键,还要注意把除法运算转化成乘法运算.
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