题目内容
先化简,再求值:(x-y)2-(y+2x)(y-2x),其中x=-1,y=
.
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(x-y)2-(y+2x)(y-2x),
=(x2-2xy+y2)-(y2-4x2)
=5x2-2xy,
∵x=-1,y=
.
∴原式=5×1+2×1×
=6.
=(x2-2xy+y2)-(y2-4x2)
=5x2-2xy,
∵x=-1,y=
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∴原式=5×1+2×1×
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