题目内容
计算:
(1)(-1)3;
(2)(-1)2012;
(3)(-0.1)3;
(4)(
)4;
(5)(-2)3×(-2)2;
(6)(-
)3×(-
)5;
(7)103;
(8)02012.
(1)(-1)3;
(2)(-1)2012;
(3)(-0.1)3;
(4)(
| 3 |
| 2 |
(5)(-2)3×(-2)2;
(6)(-
| 1 |
| 2 |
| 1 |
| 2 |
(7)103;
(8)02012.
分析:分别根据有理数的乘方的定义进行计算即可得解.
解答:解:(1)(-1)3=-1;
(2)(-1)2012=1;
(3)(-0.1)3=-0.001;
(4)(
)4=
;
(5)(-2)3×(-2)2,
=-8×4,
=-32;
(6)(-
)3×(-
)5,
=(-
)×(-
),
=
;
(7)103=1000;
(8)02012=0.
(2)(-1)2012=1;
(3)(-0.1)3=-0.001;
(4)(
| 3 |
| 2 |
| 81 |
| 16 |
(5)(-2)3×(-2)2,
=-8×4,
=-32;
(6)(-
| 1 |
| 2 |
| 1 |
| 2 |
=(-
| 1 |
| 8 |
| 1 |
| 32 |
=
| 1 |
| 256 |
(7)103=1000;
(8)02012=0.
点评:本题考查了有理数的乘方,负数的奇数次幂是负数,负数的偶数次幂是正数;-1的奇数次幂是-1,-1的偶数次幂是1.
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