题目内容
先化简,再求值| x+1 |
| x2+1 |
| (x+1)3 |
| x4-1 |
| x-3 |
| x+1 |
| 3 |
分析:先除后减,做除法时要注意先把除法运算转化为乘法运算,而做乘法运算时要注意先把分子、分母能因式分解的先分解,然后约分;做减法运算时,应是同分母,可以直接通分.最后把数代入求值.
解答:解:
÷
-
=
•
-
=
-
=
;
当x=
+1时,
原式=
=
=
=2(2-
)=4-2
.
| x+1 |
| x2+1 |
| (x+1)3 |
| x4-1 |
| x-3 |
| x+1 |
=
| x+1 |
| x2+1 |
| (x2+1)(x+1)(x-1) |
| (x+1)3 |
| x-3 |
| x+1 |
=
| x-1 |
| x+1 |
| x-3 |
| x+1 |
=
| 2 |
| x+1 |
当x=
| 3 |
原式=
| 2 |
| x+1 |
| 2 | ||
|
| 2 | ||
|
| 3 |
| 3 |
点评:考查分式的化简与求值,主要的知识点是因式分解、通分、约分等.
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