题目内容
计算:(1)(-
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 9 |
(2)
| 5 |
| 8 |
| 1 |
| 2 |
分析:做计算题时一定要遵循计算顺序,先算小括号里面的,再算乘方,再算乘除最后算加减,计算时要注意符号的确定.负数的偶次幂为正.负数的奇次幂为负.
解答:解:(1)原式=(-
)×(-
)×9×(-2),
=-(
×
×9×2),
=-2;
(2)原式=
×16-0.25×(-5)÷(-
),
=10-(-1.25)×(-8),
=10-10,
=0.
| 2 |
| 3 |
| 1 |
| 6 |
=-(
| 2 |
| 3 |
| 1 |
| 6 |
=-2;
(2)原式=
| 5 |
| 8 |
| 1 |
| 8 |
=10-(-1.25)×(-8),
=10-10,
=0.
点评:此题主要考查了有理数的乘方,乘除和加减运算,题目比较基础.
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