ÌâÄ¿ÄÚÈÝ
ÈËÀàµÄÉú²úÉú»îÀë²»¿ª½ðÊô²ÄÁÏ£¬Ëæ×ſƼ¼Ë®Æ½µÄ²»¶ÏÌá¸ß£¬½ðÊô¼°ÆäºÏ½ðÔÚÈÕ³£Éú»îÖаçÑÝ×ÅÔ½À´Ô½ÖØÒªµÄ½ÇÉ«¡£
£¨1£©ÈËÃÇϰ¹ßÉϰѽð¡¢Òø¡¢Í¡¢Ìú¡¢ÎýÎåÖÖ½ðÊôͳ³ÆÎª¡°Îå½ð¡±£¬ÔÚ¡°Îå½ð¡±Ë³ÐòÖаѽðÊô¡¡ ¡¡µÄλÖÃÒÆµ½×îºó£¬ÕýºÃ·ûºÏÓÉÈõµ½Ç¿µÄ˳Ðò£®
£¨2£©Æû³µ³µÌå¶àÓøֲÄÖÆÔì¡£±íÃæÅçÆá²»½öÃÀ¹Û£¬¶øÇÒ¿ÉÓÐЧ·ÀÖ¹Óë ½Ó´¥¶øÉúÐâ¡£
£¨3£©¹¤ÒµÉÏÓÃCO»¹Ô³àÌú¿óÒ±Á¶½ðÊôÌúµÄ»¯Ñ§·½³ÌΪ ¡£
Î÷ººÊ±ÆÚÖйú¹ÅÀϵÄұͷ½·¨ÊÇ¡°Êª·¨Ò±Í¡±Ö÷ÒªµÄ·´Ó¦ÔÀíÊÇÌúÓëÁòËáÍÈÜÒº·´Ó¦£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ
£¨4£©ÔÚʵÑéÊÒÖÐ̽¾¿ÂÁ¡¢ÍµÄ½ðÊô»î¶¯ÐÔ˳Ðò£¬³ýÂÁ¡¢ÍÍ⣬»¹ÐèÒªÓõ½µÄÊÔ¼ÁÊÇ ¡££¨ÌîÒ»ÖÖ¼´¿É£©
£¨5£©Ìú¹ø¡¢ÂÁ¹øÊÇÉú»îÖг£ÓõĴ¶¾ß£¬ÓÒͼÊÇÌú¹øµÄʾ
Òâͼ¡£
¢ÙÌú¹øº¬ÓкϽðµ¥ÖÊ_______£¨Ð´»¯Ñ§Ê½£©£¬º¬ÓеÄÓлúºÏ ³É²ÄÁÏÊÇ_________¡££¨ÌîдÃû³Æ£©
¢Ú³´²ËʱÌú¹øÖеÄÓÍ×Å»ð¿ÉÓùø¸Ç¸ÇÃð£¬ÆäÔÀíÊÇ______________________________________¡£
¢ÛÍÒ²Ò×ÉúÐ⣬ÍÐâµÄÖ÷Òª³É·ÖÊǼîʽ̼ËáÍ£¨Cu2£¨OH£©2CO3£©£¬ÊÇÍÓë¿ÕÆøÖеÄÑõÆø¡¢Ë®ºÍ¡¡ ¡¡¹²Í¬×÷ÓõĽá¹û£®
£¨1£©Ìú»òFe£¨1·Ö£© £¨2£©Ë®ºÍÑõÆø£¨1·Ö£©
£¨3£©Fe2O3 + 3CO =(¸ßÎÂ) 2Fe + 3CO2; £¨2·Ö£© Fe+CuSO
4=FeSO4+Cu£¨2·Ö£©
£¨4£©Ï¡ÑÎËá»òÏ¡ÁòËá»òÁòËáÍÈÜÒº£¨ºÏÀí¾Í¿ÉµÃ·Ö£©£¨1·Ö£©
£¨5£©¢ÙFe£¨1·Ö£© ;ËÜÁÏ£¨1·Ö£© ¢ÚʹÓÍÓëÑõÆø¸ô¾ø£¨1·Ö£© ¢ÛCO2£¨1·Ö£©
³ýÈ¥ÏÂÁÐÎïÖÊÖеÄÉÙÁ¿ÔÓÖÊ£¬ËùÑ¡ÊÔ¼Á¼°²Ù×÷¶¼ÕýÈ·µÄÊÇ
| ÐòºÅ | ÎïÖÊ | ÔÓÖÊ | ÊÔ¼Á |
|
| ||||||||
| A | FeCl2ÈÜÒº | CuCl2 | ¹ýÁ¿Ìú·Û | ½á¾§ |
| ||||||||
| B | CO2 | H2O | ŨÁòËá | Ï´Æø |
| ||||||||
| C | NaNO3ÈÜÒº | Na2CO3 | ÊÊÁ¿CaCl2ÈÜÒº | ¹ýÂË |
| ||||||||
| D | Í·Û | Ìú·Û | ¹ýÁ¿Ë® | ¹ýÂË |
| ||||||||
| ¡¡ | A£® | A¡¢ | B£® | B¡¢ | C£® | C¡¢ D. D | ||||||||