题目内容



解  (1)2.2g                                                   1分

(2)设每片含碳酸钙的质量为x                                       1分

CaCO3 + 2HCl = CaCl2 + H2O + CO2↑                         1分

100                             44           

x                               2.2g                           

    100/x = 44/2.2g                                                   1分

       x = 5g                                                      1分

样品中碳酸钙的的质量分数=5g÷ 6 g×100% = 83.3%                       1分

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