ÌâÄ¿ÄÚÈÝ


³ÆÈ¡NaClºÍBaCl2µÄ¹ÌÌå»ìºÏÎï32.5 g£¬¼ÓÈë100 gÕôÁóË®£¬ÍêÈ«ÈܽâºóÏò¸Ã»ìºÏÈÜÒºÖÐÖðµÎ¼ÓÈëÖÊÁ¿·ÖÊýΪ10%µÄNa2SO4ÈÜÒº£¬·´Ó¦Éú³ÉBaSO4³ÁµíµÄÖÊÁ¿ÓëËù¼ÓÈëµÄNa2SO4ÈÜÒºµÄÖÊÁ¿¹ØÏµÈçÏÂͼËùʾ¡£ÊԻشðÏÂÁÐÎÊÌ⣺

(Ìáʾ£ºBaCl2+Na2SO4====BaSO4¡ý+2NaCl)

(1)ÍêÈ«·´Ó¦ºóÉú³ÉBaSO4³Áµí______________g¡£

(2)Ç¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄNa2SO4ÈÜÒºµÄÖÊÁ¿ÊÇ____________________g¡£

(3)Ç¡ºÃÍêÈ«·´Ó¦Ê±ËùµÃÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿(¾«È·µ½0.1%)


±¾Ì⿼²é½áºÏͼÏñ½øÐл¯Ñ§·½³Ìʽ¼ÆËãµÄÄÜÁ¦¡£

(1)ÓÉÌâÖÐͼʾ¿ÉÖª£¬ÍêÈ«·´Ó¦ºóÉú³ÉBaSO4³ÁµíµÄÖÊÁ¿Îª23.3 g¡£

(2)¸ù¾ÝBaSO4µÄÖÊÁ¿¿ÉÇó³öÁòËáÄÆµÄÖÊÁ¿£¬¸ù¾ÝÁòËáÄÆÈÜÒºµÄÈÜÖʵÄÖÊÁ¿·ÖÊý£¬¿ÉÇóµÃÁòËáÄÆÈÜÒºµÄÖÊÁ¿¡£

(3)Ç¡ºÃÍêÈ«·´Ó¦ºó£¬ÈÜÒºÖÐÈÜÖÊÊÇÂÈ»¯ÄÆ£¬¸ù¾Ý³ÁµíµÄÖÊÁ¿£¬¿ÉÇóµÃ·´Ó¦Éú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿£¬¼ÓÉÏÔ­¹ÌÌåÖÐÂÈ»¯ÄƵÄÖÊÁ¿¼´Îª·´Ó¦ºóÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿£¬½øÒ»²½¿ÉÇóµÃÇ¡ºÃÍêÈ«·´Ó¦Ê±ËùµÃÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý¡£

´ð°¸£º(1)23.3¡¡(2)142

(3)½â£ºÉèBaCl2µÄÖÊÁ¿Îªx£¬·´Ó¦Éú³ÉµÄNaClµÄÖÊÁ¿Îªy¡£

BaCl2+Na2SO4====BaSO4¡ý+2NaCl

208          233      117

x               23.3 g  y

==

x=20.8 g¡¡y=11.7 g

Ç¡ºÃÍêÈ«·´Ó¦Ê±£¬ÈÜÒºÖÐNaClµÄÖÊÁ¿Îª

11.7 g+(32.5 g-20.8 g)=23.4 g

NaClÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊýΪ¡Á100%=9.3%

´ð£º(ÂÔ)


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø