ÌâÄ¿ÄÚÈÝ

Ëæ×Å¿ÆÑ§¼¼ÊõµÄ·¢Õ¹£¬»·±£ÎÊÌâÔ½À´Ô½ÒýÆð¸÷¹úÕþ¸®µÄÖØÊÓ£¬¹¤ÒµÎÛË®±ØÐë¾­¹ý´¦Àí£¬´ïµ½¹ú¼Ò¹æ¶¨µÄ±ê×¼ºó£¬²ÅÄÜÅÅ·Å¡£Ä³»¯Ñ§ÊÔ¼Á³§A£¬B£¬C£¬DËĸö³µ¼äÅŷŵÄÎÛË®ÖУ¬·Ö±ðº¬ÓÐÎÛȾÎïCuCl2£¬HCl£¬Na2CO3£¬NaOHÖеÄÒ»ÖÖ£¬ÏÖ¶ÔÎÛË®×÷ÈçÏ´¦Àí£º

£¨1£©½«AµÄÎÛË®ÓëBµÄÀ¶É«ÎÛˮͨÈëµÚÒ»·´Ó¦³Ø£¬²úÉúÀ¶É«³Áµí¡£

£¨2£©½«CµÄÎÛË®ÓëDµÄËáÐÔÎÛˮͨÈëµÚ¶þ·´Ó¦³Ø£¬²úÉú´óÁ¿ÆøÅÝ¡£

£¨3£©½«µÚÒ»·´Ó¦³ØÉϲãµÄ¼îÐÔÎÛË®ÓëµÚ¶þ·´Ó¦³ØÁ÷³öµÄËáÐÔÎÛˮͨÈëµÚÈý·´Ó¦³Ø£¬×îÖÕÎÛË®ÏÔÖÐÐÔ£¬ÒªÏòÍâÅÅ·Å¡£

ÊÔÍÆ¶Ï¸÷³µ¼äÎÛË®µÄÎÛȾÎï___________________________________¡£

×îÖÕÏòÍâÅŷŵÄË®Öк¬ÓеÄÈÜÖÊÊÇ_________________________________¡£

д³öµÚÈý¸ö·´Ó¦³ØÖÐËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________________________¡£

 

´ð°¸£º
½âÎö£º

A£®NaOH£»B£®CuCl2£»C£®Na2CO3£»

D£®HCl  ×îÖÕÅųö²úÎïNaCl    NaOH+HCl¨T¨TNaCl+H2O

 


Ìáʾ£º


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ú¡¢Ê¯ÓͺÍÌìÈ»ÆøÊdz£¼ûµÄÈýÖÖ»¯Ê¯È¼ÁÏ£¬ËüÃÇÊôÓÚ²»¿ÉÔÙÉúÄÜÔ´£®Ëæ×Å¿ÆÑ§¼¼ÊõµÄ·¢Õ¹ÒÔ¼°Éú²úºÍÉú»îÐèÇóµÄÔö¼Ó£¬ÈËÃÇÕýÔÚÀûÓúͿª·¢ÆäËûÐÂÄÜÔ´£®
£¨1£©Ê¯Ó;­¹ý¼ÓÈÈ·ÖÁ󣬵õ½Ê¯ÓÍÆø¡¢ÆûÓÍ¡¢ÃºÓÍ¡¢²ñÓÍ¡¢Èó»¬ÓÍ¡¢Ê¯À¯µÈ²úÆ·£¬¸Ã¹ý³ÌÊôÓÚ
ÎïÀí
ÎïÀí
±ä»¯£¨Ñ¡Ìî¡°ÎïÀí¡±»ò¡°»¯Ñ§¡±£¬ÏÂͬ£©£»½«Ãº¸ô¾ø¿ÕÆø¼ÓÈȵ½ÉÏǧÉãÊ϶ȣ¬µÃµ½½¹Â¯ÃºÆø¡¢´Ö°±Ë®¡¢½¹Ì¿ºÍú½¹ÓÍ£¬¸Ã¹ý³ÌÊôÓÚ
»¯Ñ§
»¯Ñ§
±ä»¯£®
£¨2£©ÏàͬÌõ¼þÏ£¬ÆøÌåÌå»ý±ÈµÈÓÚ·Ö×ÓÊý±È£®ÏÖÓÐÒ»Ì×ÒÔÒº»¯Ê¯ÓÍÆø£¨Ö÷Òª³É·ÖΪC4H10£©ÎªÈ¼ÁϵÄÔî¾ß£¬ÈôÒª¸ÄΪÒÔÌìÈ»ÆøÎªÈ¼ÁϵÄÔî¾ß£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ
C
C
£¨Ñ¡Ìî×Öĸ£©£®
A£®È¼ÁÏÆøºÍ¿ÕÆøµÄ½øÈëÁ¿¶¼¼õС              B£®È¼ÁÏÆøºÍ¿ÕÆøµÄ½øÈëÁ¿¶¼Ôö´ó
C£®Ôö´óȼÁÏÆø½øÈëÁ¿»ò¼õС¿ÕÆø½øÈëÁ¿        D£®¼õСȼÁÏÆø½øÈëÁ¿»òÔö´ó¿ÕÆø½øÈëÁ¿
£¨3£©º£µ×Âñ²Ø×Å´óÁ¿µÄ¡°¿Éȼ±ù¡±£¬Ö÷Òª³É·ÖÓɼ×Íé·Ö×ÓºÍË®·Ö×Ó×é³É£¬Èç¹û¿ª²É²»µ±¶øÊ¹¼×Í鯸Ìå´óÁ¿Ð¹Â©£¬»áÔì³ÉµÄÑÏÖØ»·¾³ÎÊÌâÊÇ
ÎÂÊÒЧӦ
ÎÂÊÒЧӦ
£®
£¨4£©ÓÒͼËùʾΪһÖÖ¡°½ÚÄܼõÅÅ¡±µÄÓÐЧ´ëÊ©£®ÒÒ´¼ÊôÓÚ
¿ÉÔÙÉú
¿ÉÔÙÉú
ÄÜÔ´£¨Ñ¡Ìî¡°¿ÉÔÙÉú¡±»ò¡°²»¿ÉÔÙÉú¡±£©£¬ÍêȫȼÉյĻ¯Ñ§·½³ÌʽÊÇ
C2H5OH+3O2
 µãȼ 
.
 
2CO2+3H2O
C2H5OH+3O2
 µãȼ 
.
 
2CO2+3H2O
£®

ú¡¢Ê¯ÓͺÍÌìÈ»ÆøÊdz£¼ûµÄÈýÖÖ»¯Ê¯È¼ÁÏ£¬ËüÃÇÊôÓÚ²»¿ÉÔÙÉúÄÜÔ´£®Ëæ×Å¿ÆÑ§¼¼ÊõµÄ·¢Õ¹ÒÔ¼°Éú²úºÍÉú»îÐèÇóµÄÔö¼Ó£¬ÈËÃÇÕýÔÚÀûÓúͿª·¢ÆäËûÐÂÄÜÔ´£®
£¨1£©Ê¯Ó;­¹ý¼ÓÈÈ·ÖÁ󣬵õ½Ê¯ÓÍÆø¡¢ÆûÓÍ¡¢ÃºÓÍ¡¢²ñÓÍ¡¢Èó»¬ÓÍ¡¢Ê¯À¯µÈ²úÆ·£¬¸Ã¹ý³ÌÊôÓÚ________±ä»¯£¨Ñ¡Ìî¡°ÎïÀí¡±»ò¡°»¯Ñ§¡±£¬ÏÂͬ£©£»½«Ãº¸ô¾ø¿ÕÆø¼ÓÈȵ½ÉÏǧÉãÊ϶ȣ¬µÃµ½½¹Â¯ÃºÆø¡¢´Ö°±Ë®¡¢½¹Ì¿ºÍú½¹ÓÍ£¬¸Ã¹ý³ÌÊôÓÚ________±ä»¯£®
£¨2£©ÏàͬÌõ¼þÏ£¬ÆøÌåÌå»ý±ÈµÈÓÚ·Ö×ÓÊý±È£®ÏÖÓÐÒ»Ì×ÒÔÒº»¯Ê¯ÓÍÆø£¨Ö÷Òª³É·ÖΪC4H10£©ÎªÈ¼ÁϵÄÔî¾ß£¬ÈôÒª¸ÄΪÒÔÌìÈ»ÆøÎªÈ¼ÁϵÄÔî¾ß£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ________£¨Ñ¡Ìî×Öĸ£©£®
A£®È¼ÁÏÆøºÍ¿ÕÆøµÄ½øÈëÁ¿¶¼¼õС¡¡¡¡¡¡¡¡¡¡¡¡¡¡B£®È¼ÁÏÆøºÍ¿ÕÆøµÄ½øÈëÁ¿¶¼Ôö´ó
C£®Ôö´óȼÁÏÆø½øÈëÁ¿»ò¼õС¿ÕÆø½øÈëÁ¿¡¡¡¡¡¡¡¡D£®¼õСȼÁÏÆø½øÈëÁ¿»òÔö´ó¿ÕÆø½øÈëÁ¿
£¨3£©º£µ×Âñ²Ø×Å´óÁ¿µÄ¡°¿Éȼ±ù¡±£¬Ö÷Òª³É·ÖÓɼ×Íé·Ö×ÓºÍË®·Ö×Ó×é³É£¬Èç¹û¿ª²É²»µ±¶øÊ¹¼×Í鯸Ìå´óÁ¿Ð¹Â©£¬»áÔì³ÉµÄÑÏÖØ»·¾³ÎÊÌâÊÇ________£®
£¨4£©ÓÒͼËùʾΪһÖÖ¡°½ÚÄܼõÅÅ¡±µÄÓÐЧ´ëÊ©£®ÒÒ´¼ÊôÓÚ________ÄÜÔ´£¨Ñ¡Ìî¡°¿ÉÔÙÉú¡±»ò¡°²»¿ÉÔÙÉú¡±£©£¬ÍêȫȼÉյĻ¯Ñ§·½³ÌʽÊÇ________£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø