ÌâÄ¿ÄÚÈÝ
С±øÔÚÒ»±¾²Î¿¼ÊéÉÏ·¢ÏÖ£¬Ã¾¾ÓÈ»ÄÜÔÚ¶þÑõ»¯Ì¼ÆøÌåÖÐȼÉÕ£¡ÓÚÊÇËûÆÈ²»¼°´ýµÄ×öÆðÁËÕâ¸öʵÑ飺½«Ã¾ÌõµãȼºóѸËÙÉìÈëÊ¢ÓжþÑõ»¯Ì¼µÄ¼¯ÆøÆ¿ÖУ¬·¢ÏÖþÌõ¾çÁÒȼÉÕ£¬·¢³ö°×¹â£¬·ÅÈÈ£¬²úÉúÒ»ÖÖ°×É«·ÛÄ©ºÍÒ»ÖÖºÚÉ«·ÛÄ©£®
£¨1£© ¸ù¾ÝʵÑéÏÖÏó£¬ÎÒÄÜд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º _________ £®
£¨2£© Õâ¸öʵÑ黹Òý·¢ÁËÎÒ¶Ô¹ýȥijЩ֪ʶµÄ·´Ë¼£¬´Ó¶øÓÐЩеķ¢ÏÖ£º¢Ù _________ £»¢Ú _________ £®
£¨1£© ¸ù¾ÝʵÑéÏÖÏó£¬ÎÒÄÜд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º _________ £®
£¨2£© Õâ¸öʵÑ黹Òý·¢ÁËÎÒ¶Ô¹ýȥijЩ֪ʶµÄ·´Ë¼£¬´Ó¶øÓÐЩеķ¢ÏÖ£º¢Ù _________ £»¢Ú _________ £®
£¨1£©2Mg+CO2
2MgO+C£»
£¨2£©È¼ÉÕ²»Ò»¶¨ÔÚÑõÆøÖнøÐУ»¶þÑõ»¯Ì¼²»ÄÜÓÃÀ´ÆËÃðþȼÉÕ£®
£¨2£©È¼ÉÕ²»Ò»¶¨ÔÚÑõÆøÖнøÐУ»¶þÑõ»¯Ì¼²»ÄÜÓÃÀ´ÆËÃðþȼÉÕ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿