ÌâÄ¿ÄÚÈÝ

£¨20·Ö£©ÊµÑéÊÒ³£ÓÃÏÂÁÐ×°ÖÃÖÆÈ¡ÆøÌ壬ÇëÄã¸ù¾ÝËùѧ֪ʶ»Ø´ðÏÂÁÐÎÊÌâ¡£

£¨1£©Ð´³ö±àºÅËùÖ¸ÒÇÆ÷µÄÃû³Æ£º¢Ù               £»¢Ú             ¡£
£¨2£©ÒÔÉÏ×°ÖÃͼÖй²ÓÐÁ½´¦Ã÷ÏԵĴíÎó£¬ÇëÄãÕÒ³ö´íÎóµÄµØ·½²¢°Ñ¸ÄÕýµÄ½á¹ûÌîÔÚÏÂÁкáÏßÉÏ£º
¢Ù                             £»¢Ú                                                                       ¡£
ÉÏÊö×°ÖøĽøºó£¬Çë¼ÌÐø»Ø´ðÏÂÁÐÎÊÌâ¡£
£¨3£©Ð¡ºìÔÚʵÑéÊÒÖÐÑ¡ÓÃC×°ÖÃ×÷ΪÑõÆøµÄ·¢Éú×°Öá£ÊµÑéÖÐËýÓõ½ÁËÒ»ÖÖ¹ÌÌåÒ©Æ·ÊÇ
           £¨Ìѧʽ£©£¬ÔÚ·´Ó¦ÖÐËüÆð                   ×÷Óá£ÇëÄãд³öСºìÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³Ìʽ£º                                                 ¡£
£¨4£©ÊµÑéÊÒÑ¡ÓÃCºÍE×°Öû¹¿ÉÒÔÖÆÈ¡µÄÆøÌåÊÇ         £¨Ìѧʽ£©£¬Ð´³öʵÑéÊÒÖÆÈ¡¸ÃÆøÌåµÄ»¯Ñ§·½³Ìʽ                                                  ¡£
£¨5£©×°ÖÃB¡¢C¶¼¿ÉÒÔÓÃÀ´ÖÆÈ¡£¨4£©ÖÐµÄÆøÌ壬±È½ÏÕâÁ½¸ö×°ÖõIJ»Í¬£¬Ö¸³öB×°ÖõÄÒ»¸öÍ»³öÓŵ㠠                                                         ¡£
£¨6£©ÓÐÒ»ÃûͬѧÓûÓÃG×°Öã¨ÈçͼËùʾ£©ÊÕ¼¯CO2£¬ÔòCO2Ó¦´Óµ¼¹Ü¿Ú      Í¨Èë¡£
£¨20·Ö£©£¨1£©³¤¾±Â©¶· ¼¯ÆøÆ¿£¨2£©A×°ÖÃÊԹܿÚδÂÔÏòÏÂÇãб£¬B×°Öõ¼¹Üδ¶ËδÉìÈë½üÆ¿µ×¡££¨3£©MnO2£¬´ß»¯£¬£¬CO2£¬ CaCO3 + 2HCl£¨Ï¡£©="==" CaCl2 + H2O + CO2¡ü£¬ÄÜ¿ØÖÆ·´Ó¦µÄ¿ªÊ¼ºÍ½áÊø£¬b

ÊÔÌâ·ÖÎö£º1¡¢±àºÅËùÖ¸ÒÇÆ÷µÄÃû³Æ£º¢Ù£»³¤¾±Â©¶·£¬¢Ú¼¯ÆøÆ¿£»
2¡¢ÌâÖÐ×°ÖÃͼµÄ´íÎóÓУºA×°ÖÃÊԹܿÚδÂÔÏòÏÂÇãб£»E×°Öõ¼¹Üδ¶ËδÉìÈë½üÆ¿µ×£»
3¡¢C×°ÖÃÊÊÓÃÓÚ¹ÌÌåºÍÒºÌå·´Ó¦ÖÆÈ¡ÆøÌ壬СºìÔÚʵÑéÊÒÖÐÑ¡ÓÃC×°ÖÃ×÷ΪÑõÆøµÄ·¢Éú×°Öã¬Ëý»áÓõ½µÄ¹ÌÌåÒ©Æ·ÊǶþÑõ»¯ÃÌ£¨MnO2£©£¬¶þÑõ»¯ÃÌÔÚ·´Ó¦ÖÐÆð´ß»¯×÷Ó㬸÷´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º£»
4¡¢ÊµÑéÊÒÑ¡ÓÃCºÍE×°Öû¹¿ÉÒÔÖÆÈ¡¶þÑõ»¯Ì¼ÆøÌ壨CO2£©£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3 + 2HCl£¨Ï¡£©="==" CaCl2 + H2O + CO2¡ü£»
5¡¢×°ÖÃB¡¢C¶¼¿ÉÒÔÓÃÀ´ÖÆÈ¡¶þÑõ»¯Ì¼ÆøÌ壬B×°ÖõÄÒ»¸öÍ»³öÓŵãÊÇÄÜ¿ØÖÆ·´Ó¦µÄ¿ªÊ¼ºÍ½áÊø£»
6¡¢Òò¶þÑõ»¯Ì¼µÄÃܶȴóÓÚ¿ÕÆø£¬ËùÒÔÈôÓÃG×°Öã¨ÈçͼËùʾ£©ÊÕ¼¯CO2£¬ÔòCO2Ó¦´Óµ¼¹Ü¿ÚbͨÈë¡£
µãÆÀ£º¸ù¾ÝÆøÌåµÄÐÔÖÊÀ´Ñ¡ÔñÖÆÈ¡¡¢ÊÕ¼¯ÆøÌåµÄ×°Öã¬G×°ÖÃÓÃ;½Ï¶à£¬×¢ÒâÇø·Ö¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨14·Ö£©Ä³Ñ§Ï°Ð¡×éÍê³É¡°ÊµÑé»î¶¯1ÑõÆøµÄʵÑéÊÒÖÆÈ¡ÓëÐÔÖÊ¡±½øÐÐÁËÑÐÌÖ¡£ÇëÄã²ÎÓëÍê³ÉÏÂÃæµÄÎÊÌâ¡£

£¨1£©Ð´³öͼÖÐÖ¸¶¨ÒÇÆ÷µÄÃû³Æ£º¢Ù_______________£»¢Ú_______________¡£
£¨2£©ÈôÑ¡Ôñ×°ÖÃAÓøßÃÌËá¼ØÖÆÈ¡ÑõÆø£¬ÔòÊԹܿÚÒª·ÅÒ»ÍÅ_______£¬¸Ã·´Ó¦µÄÎÄ×Ö±í´ïʽΪ_______________________________________£»ÊÕ¼¯´¿¶È¸ßµÄÑõÆøÒËÑ¡ÓÃ____£¨ÌîÐòºÅ£¬ÏÂͬ£©¡£
£¨3£©Èç¹ûÓÃË«ÑõË®¡¢¶þÑõ»¯ÃÌÖÆÑõÆø£¬ÔòÑ¡Óõķ¢Éú×°ÖÃÊÇ____£»·´Ó¦µÄÎÄ×Ö±í´ïʽΪ________________________¡£
£¨4£©ÓÃÅÅ¿ÕÆø·¨ÊÕ¼¯ÑõÆø£¬ÑéÂúµÄ·½·¨ÊÇ_________________________________________¡£
£¨5£©FͼÊÇijͬѧ¼ÓÈÈÂÈËá¼ØÖÆÈ¡ÑõÆøµÄ×°Öã¬Ö¸³öÆäÖеĴíÎó__________________£»Òª¸ÄÕý´íÎóÐèÒª²Ù×÷µÄ°´Å¥ÊÇ_______£¨Ìî×Öĸ£©¡£

£¨6£©ÊµÑé²Ù×÷£ºÓøßÃÌËá¼ØÖÆÈ¡ÑõÆøµÄ²Ù×÷¹ý³Ì¿É¸ÅÀ¨Îª£º¡°×é×°ÒÇÆ÷¡ú            ¡ú×°Ò©Æ·ºÍ·ÅÃÞ»¨²¢¹Ì¶¨ÊԹܡú¼ÓÈÈÊԹܡúÊÕ¼¯ÆøÌå¡ú½«µ¼¹Ü´ÓË®²ÛÖÐÈ¡³ö¡úÍ£Ö¹¼ÓÈÈ¡±¡£
£¨7£©ÊµÑ鷴˼£ºÔÚ¼ÓÈÈÂÈËá¼ØÖÆÈ¡ÑõÆøµÄ¹ý³ÌÖУ¬·¢ÏÖ²úÉúÑõÆøµÄËÙÂʺÜÂý£¬¾­¼ì²é²»ÊÇÂÈËá¼Ø±äÖÊ£¬Ò²²»ÊÇ×°ÖÃÆøÃÜÐÔ²»ºÃ£¬ÄãÈÏΪ×î¿ÉÄܵÄÔ­ÒòÊÇ                    ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø