ÌâÄ¿ÄÚÈÝ

ÊÀ²©Ô°ÇøÄÚÓÐÐí¶àÒûˮ̨£¬¿ÉÖ±½ÓȡˮÒûÓá£ÆäÖеÄÒûÓÃË®´¦Àí²½ÖèÈçÏÂͼËùʾ¡£

 

 

£¨1£©¢ÙÖлîÐÔÌ¿µÄ×÷ÓÃÊÇ          £¬¢ÛÖÐ×ÏÍâµÆ¹ÜÕÕÉäµÄ×÷ÊÇ                      ¡£

£¨2£©ÊÀ²©»áÉÏÓÐǧÁ¾ÐÂÄÜÔ´Æû³µÍ¶ÈëÔËÐУ¬ÆäÖв¿·Ö¹«½»³µ²ÉÓöþ¼×ÃÑ(C2H6O)×÷ȼÁÏ¡£¶þ¼×ÃÑÍêȫȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡¡¡¡¡¡¡¡¡¡              ¡££¨3£©¿óȪˮ¡¢ÕôÁóË®ÓжàÖÖ×÷Óã¬ÀýÈ磺þÓëµâµÄ»¯ºÏ·´Ó¦Ê®·Ö»ºÂý£¬ÈôµÎ¼ÓÉÙÁ¿Ë®£¬Ôò·´Ó¦Á¢¼´¾çÁÒ½øÐУ¬·´Ó¦ËÙ¶È´ó´óÌá¸ß£¬´ËʱˮµÄ×÷ÓÃÊÇ¡¡¡¡¡¡¡¡       ¡£

 

¡¾´ð°¸¡¿

£¨1£©Îü¸½    ɱ¾úÏû¶¾                                     £¨2·Ö£©

£¨2£©C2H6O + 3O22CO2 + 3 H2O                                 £¨1·Ö£©

£¨3£©´ß»¯¼Á                                                         £¨1·Ö£©

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
2010Äê4ÔÂ14ÈÕÇຣÓñÊ÷·¢Éú7.1¼¶µØÕð£¬ÔÖÇøÒûÓÃË®°²È«±¸ÊܹØ×¢£®
£¨1£©ÌìȻˮÖк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ
ÕôÁó
ÕôÁó
£®
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖпÉÓÃ
·ÊÔíË®
·ÊÔíË®
À´Çø·ÖӲˮºÍÈíË®£¬³£ÓÃ
¼ÓÈÈÖó·Ð»òÕôÁó
¼ÓÈÈÖó·Ð»òÕôÁó
µÄ·½·¨À´½µµÍË®µÄÓ²¶È£®
£¨3£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚÔÖÇø·ÀÒߣ®ÖƱ¸ÆäÖ÷Òª³É·Ö´ÎÂÈËáÄÆ£¨NaClO£©µÄ»¯Ñ§·½³ÌʽΪ£»
2NaOH+X¨TNaClO+NaCl+H2O£¬ÔòXµÄ»¯Ñ§Ê½Îª
Cl2
Cl2
£»
£¨4£©ÊÀ²©Ô°ÇøÄÚÓÐÐí¶àÒûˮ̨£¬¿Éȡˮֱ½ÓÒûÓã®ÆäÖеÄÒûÓÃË®´¦Àí²½ÖèÈçÏÂͼËùʾ£»

²½Öè¢Ù¶ÔÓ¦µÄ×÷ÓÃÊÇ
B
B
£¨Ìî×Öĸ£®ÏÂͬ£©£¬²½Öè¢Û¶ÔÓ¦µÄ×÷ÓÃÊÇ
A
A
£®
A£®É±¾úÏû¶¾        B£®Îü¸½ÔÓÖÊ
£¨5£©Ðí¶àʵÑéÖж¼Óõ½ÁËË®£¬ÇëÖ¸³öÏÂÃæ¼×¡¢ÒÒÁ½Í¼ËùʾʵÑéÖÐË®µÄ×÷Óã®
¼×ͼÖУº
Ϊ·ÀÖ¹Éú³ÉµÄ¹ÌÌ彦ÂäʱըÁѼ¯ÆøÆ¿µ×
Ϊ·ÀÖ¹Éú³ÉµÄ¹ÌÌ彦ÂäʱըÁѼ¯ÆøÆ¿µ×
£»
ÒÒͼÖУº
¼ÓÈÈʹ°×Á×µÄζÈÉÏÉýµ½Æä×Å»ðµãÒÔÉÏ
¼ÓÈÈʹ°×Á×µÄζÈÉÏÉýµ½Æä×Å»ðµãÒÔÉÏ
£®
£¨6£©Ñ¡Ò»Ð´³ö£¨5£©ÌâÖм׻òÒÒËù·¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³Ìʽ
3Fe+2O2
 µãȼ 
.
 
Fe3O4»ò4P+5O2
 µãȼ 
.
 
2P2O5
3Fe+2O2
 µãȼ 
.
 
Fe3O4»ò4P+5O2
 µãȼ 
.
 
2P2O5
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø