ÌâÄ¿ÄÚÈÝ

ijÐËȤС×éµÄͬѧÔÚʵÑéÊÒÓú¬ÓÐÉÙÁ¿Éúʯ»ÒµÄÂÈ»¯ÄƹÌÌåÅäÖÆÒ»¶¨ÖÊÁ¿·ÖÊýµÄÂÈ»¯ÄÆÈÜÒº¡£ÊµÑé²½ÖèÈçÏÂͼËùʾ£º

Çë»Ø´ð£º

£¨1£©ÔÚ¡°¹ÌÌåÑùÆ·¡±ÖмÓÈëˮʱËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ        ¡£

£¨2£©¡°ÈÜÒºA¡±ÖÐËùº¬ÈÜÖÊΪ        £¨Ìѧʽ£©¡£

£¨3£©ÔÚ¡°²Ù×÷2¡±ÖУ¬ÒªÓõ½µÄ²£Á§ÒÇÆ÷³ý²£Á§°ô¡¢ÉÕ±­Í⣬»¹ÓР       ¡£

£¨4£©¼ÓÈë¡°ÊÊÁ¿Ï¡HCl¡±µÄÄ¿µÄÊÇ        ¡£

£¨5£©¡°³ÁµíC¡±ÊÇ        £¨Ìѧʽ£©¡£

£¨6£©¡°²Ù×÷3¡±µÄÃû³ÆÊÇ        ¡£

£¨7£©¢ÙÓÃÌá´¿µÄNaClÅäÖÆ200 g 0.9£¥µÄÉúÀíÑÎË®£¬ÐèÒªNaClµÄÖÊÁ¿Îª        g¡£

¢ÚÓÃÍÐÅÌÌìÆ½³ÆÁ¿ËùÐèµÄÂÈ»¯ÄÆÊ±£¬·¢ÏÖÍÐÅÌÌìÆ½µÄÖ¸ÕëÆ«Ïò×óÅÌ£¬Ó¦        ¡£

         A£®Ôö¼ÓÊÊÁ¿íÀÂë       B£®¼õÉÙÊÊÁ¿ÂÈ»¯ÄƹÌÌå        C£®µ÷½ÚƽºâÂÝĸ

¢ÛÔÚÓÃÁ¿Í²Á¿È¡ËùÐèË®µÄ¹ý³ÌÖУ¬Èô¸©ÊÓ¶ÁÊý£¬¶øÆäÓà²Ù×÷¾ùÕýÈ·£¬ÕâÑùÅäµÃµÄÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý»á        £¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±¡¢»ò¡°ÎÞÓ°Ï족£©¡£

£¨1£©CaO+ H2O === Ca(OH)2£¨2£©Ca(OH)2ºÍNaCl£»£¨3£©Â©¶·£¨4£©³ýÈ¥ÈÜÒºÖеÄÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆ

£¨5£©CaCO3£¨6£©Õô·¢£¨7£©¢Ù1.8 ¢ÚB ¢ÛÆ«¸ß

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø