ÌâÄ¿ÄÚÈÝ

¿ÎÍâ»î¶¯Ð¡×éµÄͬѧÔڲⶨÓÉNaClºÍNa2CO3ÐγɵĹÌÌå»ìºÏÎï×é³Éʱ£¬½øÐÐÁËÒÔÏÂʵÑ飺ȡ40 g¹ÌÌå»ìºÏÎïÅä³ÉÈÜÒº£¬Æ½¾ù·ÖΪËÄ·Ý£¬È»ºó·Ö±ð¼ÓÈëÒ»¶¨ÖÊÁ¿·ÖÊýµÄCaCl2ÈÜÒº£¬ÊµÑéÊý¾Ý¼ûÏÂ±í£º
ʵÑéÒ» ʵÑé¶þ ʵÑéÈý ʵÑéËÄ
Ô­¹ÌÌå»ìºÏÎïÖÊÁ¿ 10g 10g 10g 10g
¼ÓÈëCaCl2ÈÜÒºÖÊÁ¿ 10g 20g 30g 40g
Éú³ÉµÄ³ÁµíµÄÖÊÁ¿ 2g m 5g 5g
Çë·ÖÎö±íÖÐÊý¾Ý»Ø´ð²¢¼ÆËã[£¨4£©ÒªÇóд¼ÆËã¹ý³Ì]
£¨1£©Éú³ÉµÄ³ÁµíÊÇ£¨Ìîд»¯Ñ§Ê½£©______£®
£¨2£©10gÔ­¹ÌÌå»ìºÏÎïÅä³ÉµÄÈÜÒººÍ×ãÁ¿CaCl2ÈÜÒº·´Ó¦£¬×î¶àÉú³É³ÁµíÖÊÁ¿Îª______g£®
£¨3£©m=______g£®
£¨4£©Ô­¹ÌÌå»ìºÏÎïÖÐNa2CO3µÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿
£¨1£©¾ÝÌâÒâ¿ÉÖª´Ë·´Ó¦µÄ·½³ÌʽΪCaCl2+Na2CO3=CaCO3¡ý+2NaCl£¬¹Ê³ÁµíÎïÊÇCaCO3£¨1·Ö£©£®
£¨2£©¾Ýͼ±í¿ÉÖª£¬¼ÓÈëCaCl2ÈÜÒºµÄÖÊÁ¿µ½30gºÍ40gʱµÄ³ÁµíÖÊÁ¿Ò»Ñù¶à£¬ËµÃ÷¼Óµ½30g ʱÒÑÍêÈ«·´Ó¦£¬¹Ê×î¶àÉú³É³ÁµíÖÊÁ¿Îª5g£¨2·Ö£©
£¨3£©ÔÚ·´Ó¦¹ý³ÌÖУ¬²Î¼Ó·´Ó¦µÄÎïÖÊÓëÉú³ÉÎïµÄÖÊÁ¿³ÉÕý±È£¬Òò´Ë
10
2
=
20
m
£¬¹Êm=4g£®£¨2·Ö£©
£¨4£©Éè10gÔ­¹ÌÌå»ìºÏÎïÖÐNa2CO3ÖÊÁ¿Îªx
CaCl2+Na2CO3=CaCO3¡ý+2NaCl
------106----100
-------x-----5g£¨1·Ö£©
106
x
=
100
5g
£¨1·Ö£©
½âÖ®µÃx=5.3g£¨1·Ö£©
5.3g
10g
¡Á100%=53%£¨2·Ö£©
´ð£ºÔ­¹ÌÌå»ìºÏÎïÖÐNa2CO3µÄÖÊÁ¿·ÖÊýÊÇ53%£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø