ÌâÄ¿ÄÚÈÝ
(8·Ö)A¡ªFºÍX¶¼ÊdzõÖл¯Ñ§Öеij£¼ûÎïÖÊ£¬ÆäÖÐA¡¢CÊÇÎÞÉ«ÆøÌ壬BΪºìÉ«·ÛÄ©£¬ËüÃǵÄת»¯¹ØÏµÈçÏÂͼËùʾ£¨²¿·ÖÉú³ÉÎïÒÑÂÔÈ¥£©£º![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ ¡£
£¨2£©º¬DµÄÉú²ú¡¢Éú»îÓÃÆ·¸¯Ê´µÄ¹ý³Ì£¬Êµ¼ÊÉÏÊÇDÓë¿ÕÆøÖеÄ
·¢Éú»¯Ñ§·´Ó¦µÄ¹ý³Ì¡£
£¨3£©Ð´³öCÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ
¡£
£¨4£©ÈôFÎªÆøÌåµ¥ÖÊ£¬Çëд³ö·´Ó¦¢ÚµÄ»¯Ñ§·½³Ìʽ
¸Ã·´Ó¦ÊôÓÚ £¨Ìîд»ù±¾·´Ó¦ÀàÐÍ£©·´Ó¦
£¨1£©Fe2O3+3CO
2Fe+3CO2 (2·Ö)
£¨2£©ÑõÆøºÍË®ÕôÆø£¨È«¶Ô²Å¸ø·Ö£¬1·Ö£©
£¨3£©CO2£«2NaOH="Na2CO3+" H2O(CO2£«NaOH=NaHCO3ͬÑù¸ø·Ö)£¨2·Ö£©
£¨4£©Fe+H2SO4£½FeSO4+H2¡ü£¨»òFe+2HCl£½FeCl2+H2¡ü,ºÏÀí¼´¿É£©£¨2·Ö£©
Öû»£¨1·Ö£©
½âÎö
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿