ÌâÄ¿ÄÚÈÝ
ÂÈ»¯ÄÆÊÇÈÕ³£Éú»îµÄ±ØÐèÆ·£¬Ò²ÊÇÖØÒªµÄ»¯¹¤ÔÁÏ¡£
(1)´ÖÑγýº¬NaClÍ⣬»¹º¬ÓÐÉÙÁ¿MgCl2¡¢CaCl2¡¢Na2SO4ÒÔ¼°ÄàɳµÈÔÓÖÊ¡£ÒÔÏÂÊÇ´ÖÑÎÌá´¿µÄ²Ù×÷Á÷³Ì¡£
(1)´ÖÑγýº¬NaClÍ⣬»¹º¬ÓÐÉÙÁ¿MgCl2¡¢CaCl2¡¢Na2SO4ÒÔ¼°ÄàɳµÈÔÓÖÊ¡£ÒÔÏÂÊÇ´ÖÑÎÌá´¿µÄ²Ù×÷Á÷³Ì¡£
ÌṩµÄÊÔ¼Á£ºNa2CO3ÈÜÒº¡¢K2CO3ÈÜÒº¡¢NaOHÈÜÒº¡¢BaCl2ÈÜÒº¡¢Ba(NO3)2ÈÜÒº¡¢±¥ºÍ
NaClÈÜÒº¡£
¢ÙÓû³ýÈ¥ÈÜÒºIÖеÄMgCl2¡¢CaCl2¡¢Na2SO4£¬´ÓÌṩµÄÊÔ¼ÁÖÐÑ¡³öaËù´ú±íµÄÊÔ¼Á£¬°´µÎ¼Ó˳ÐòÒÀ´ÎΪ£º___________¡¢___________£»
¢ÚÔÚÂËÒºÖмÓÑÎËáµÄ×÷ÓÃÊÇ_______________________£»
(2)ÓÃÌá´¿µÄNaClÅäÖÆ200g0.9£¥µÄÉúÀíÑÎË®£¬ÐèÒªNaClµÄÖÊÁ¿Îª__________ g¡£
¢ÙÅäÖÆ¸ÃÈÜҺʱËùÐèÒªµÄ²£Á§ÒÇÆ÷Óв£Á§°ô¡¢________ºÍ_________ £¬ÆäÖв£Á§°ôÔÚ¸ÃʵÑéÖÐËùÆðµÄ×÷ÓÃÊÇ____________¡£
¢ÚÈç¹ûÅäÖÆºóÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊýµÍÓÚ0.9£¥£¬ÄãÈÏΪ¿ÉÄܵÄÔÒòÊÇ_____________________________¡£(ÈÎдһ¸ö)
NaClÈÜÒº¡£
¢ÙÓû³ýÈ¥ÈÜÒºIÖеÄMgCl2¡¢CaCl2¡¢Na2SO4£¬´ÓÌṩµÄÊÔ¼ÁÖÐÑ¡³öaËù´ú±íµÄÊÔ¼Á£¬°´µÎ¼Ó˳ÐòÒÀ´ÎΪ£º___________¡¢___________£»
¢ÚÔÚÂËÒºÖмÓÑÎËáµÄ×÷ÓÃÊÇ_______________________£»
(2)ÓÃÌá´¿µÄNaClÅäÖÆ200g0.9£¥µÄÉúÀíÑÎË®£¬ÐèÒªNaClµÄÖÊÁ¿Îª__________ g¡£
¢ÙÅäÖÆ¸ÃÈÜҺʱËùÐèÒªµÄ²£Á§ÒÇÆ÷Óв£Á§°ô¡¢________ºÍ_________ £¬ÆäÖв£Á§°ôÔÚ¸ÃʵÑéÖÐËùÆðµÄ×÷ÓÃÊÇ____________¡£
¢ÚÈç¹ûÅäÖÆºóÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊýµÍÓÚ0.9£¥£¬ÄãÈÏΪ¿ÉÄܵÄÔÒòÊÇ_____________________________¡£(ÈÎдһ¸ö)
(1)¢ÙBaCl2ÈÜÒº ¡¢ Na2CO3ÈÜÒº£»¢Ú³ýÈ¥¹ýÁ¿µÄNaOHºÍNa2CO3
(2)1.8£»Á¿Í²£»ÉÕ±£»½Á°è£¬¼ÓËÙÈܽ⣻ ÓÃÁ¿Í²Á¿È¡Ë®Ê±ÑöÊÓ¶ÁÊý (»òÉÕ±ÖÐÓÐË®¡¢ÂÈ»¯ÄÆÖлìÓÐÔÓÖÊµÈÆäËûºÏÀí´ð°¸)
(2)1.8£»Á¿Í²£»ÉÕ±£»½Á°è£¬¼ÓËÙÈܽ⣻ ÓÃÁ¿Í²Á¿È¡Ë®Ê±ÑöÊÓ¶ÁÊý (»òÉÕ±ÖÐÓÐË®¡¢ÂÈ»¯ÄÆÖлìÓÐÔÓÖÊµÈÆäËûºÏÀí´ð°¸)
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿