ÌâÄ¿ÄÚÈÝ
д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬²¢Ìî¿Õ¡£
(1)ÓÃË«ÑõË®ºÍ¶þÑõ»¯ÃÌÖÆ±¸ÑõÆø£º_______£»·´Ó¦ÀàÐÍÊÇ_______¡£
(2)´¿¼îÈÜÒºÓëʯ»ÒË®·´Ó¦£º_______£»¹Û²ìµ½µÄÏÖÏóÊÇ_______¡£
(3)ÈýÑõ»¯ÁòÓëË®·´Ó¦£º_______£»·´Ó¦ºóÈܽâµÄpH_______7£¨Ñ¡Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©¡£
(4)¸ßÎÂʱÓÃÒ»Ñõ»¯Ì¼»¹ÔÑõ»¯Ìú£º_______£»·´Ó¦ºóµÄÆøÌåͨÈë³ÎÇåʯ»ÒË®ÖеÄÏÖÏóÊÇ_______¡£
(5)̼ÔÚ¹ýÁ¿ÑõÆøÖгä·ÖȼÉÕ£º_______£»¸Ã·´Ó¦ÊôÓÚ_______£®£¨Ñ¡Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©·´Ó¦¡£
(1)2H2O2
2H2O£«O2¡ü ·Ö½â·´Ó¦
(2)Na2CO3£«Ca(OH)2£½CaCO3¡ý£«2NaOH Óа×É«³ÁµíÉú³É
(3)H2O£«SO3£½H2SO4 СÓÚ
(4)3CO£«Fe2O3
2Fe£«3CO2 ³ÎÇåʯ»ÒË®±ä»ë×Ç
(5)C£«O2
CO2 ·ÅÈÈ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2009?¦µ×£©Ð¡ÀèͬѧΪÁ˽øÒ»²½¼ÓÉî¶Ô¡°¼îµÄ»¯Ñ§ÐÔÖÊ¡±µÄÀí½â£¬ÌØÑûÄãÐÖúÍê³ÉÏÂÁлÓë̽¾¿£º
£¨1£©ÈçͼËùʾ£¬ÔÚ°×É«µãµÎ°åÉϽøÐÐʵÑ飬Ç뽫ʵÑéÏÖÏóÌîÈëÏÂ±í£º
£¨2£©»ØÒä¼ìÑé¶þÑõ»¯Ì¼ÆøÌåµÄ·´Ó¦£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½ ³Ìʽ______£®
£¨3£©ÈýÑõ»¯Áò£¨SO3£©ÓëÇâÑõ»¯ÄÆ·´Ó¦ÓëÉÏÃæµÄ·´Ó¦ÀàËÆ£¬Ð´³öÕâÒ»·´Ó¦µÄ»¯Ñ§·½³Ìʽ______£®
£¨4£©ÈçͼËùʾ£¬ÔÚÉÕ±ÖмÓÈë10mLÇâÑõ»¯ÄÆÈÜÒº£¬µÎÈ뼸µÎ·Ó̪ÊÔÒº£¬ÈÜÒºÏÔ______É«£¬ÔÙÓõιÜÂýÂýµÎÈëÏ¡ÑÎËᣬ²¢²»¶Ï½Á°èÈÜÒº£¬ÖÁÈÜÒºÑÕɫǡºÃ±ä³ÉÎÞɫΪֹ£®ÕâһʵÑé˵Ã÷£ºËáÓë¼î×÷ÓÃÉú³ÉÁËÑκÍË®£¬ÕâÒ»·´Ó¦½Ð×ö______·´Ó¦£®
£¨5£©¸ù¾ÝÉÏÃæµÄʵÑéºÍÌÖÂÛ£¬ÊÔ¹éÄɳöÇâÑõ»¯ÄÆ¡¢ÇâÑõ»¯¸ÆÓÐÄÄЩÏàËÆµÄ»¯Ñ§ÐÔÖÊ£®£¨ÈÎдÁ½µã£©?
¢Ù______
¢Ú______£®

£¨1£©ÈçͼËùʾ£¬ÔÚ°×É«µãµÎ°åÉϽøÐÐʵÑ飬Ç뽫ʵÑéÏÖÏóÌîÈëÏÂ±í£º
| ÇâÑõ»¯ÄÆÈÜÒº | ÇâÑõ»¯¸ÆÈÜÒº | |
| ¼Ó×ÏɫʯÈïÈÜÒº | ______ | ______ |
£¨3£©ÈýÑõ»¯Áò£¨SO3£©ÓëÇâÑõ»¯ÄÆ·´Ó¦ÓëÉÏÃæµÄ·´Ó¦ÀàËÆ£¬Ð´³öÕâÒ»·´Ó¦µÄ»¯Ñ§·½³Ìʽ______£®
£¨4£©ÈçͼËùʾ£¬ÔÚÉÕ±ÖмÓÈë10mLÇâÑõ»¯ÄÆÈÜÒº£¬µÎÈ뼸µÎ·Ó̪ÊÔÒº£¬ÈÜÒºÏÔ______É«£¬ÔÙÓõιÜÂýÂýµÎÈëÏ¡ÑÎËᣬ²¢²»¶Ï½Á°èÈÜÒº£¬ÖÁÈÜÒºÑÕɫǡºÃ±ä³ÉÎÞɫΪֹ£®ÕâһʵÑé˵Ã÷£ºËáÓë¼î×÷ÓÃÉú³ÉÁËÑκÍË®£¬ÕâÒ»·´Ó¦½Ð×ö______·´Ó¦£®
£¨5£©¸ù¾ÝÉÏÃæµÄʵÑéºÍÌÖÂÛ£¬ÊÔ¹éÄɳöÇâÑõ»¯ÄÆ¡¢ÇâÑõ»¯¸ÆÓÐÄÄЩÏàËÆµÄ»¯Ñ§ÐÔÖÊ£®£¨ÈÎдÁ½µã£©?
¢Ù______
¢Ú______£®