ÌâÄ¿ÄÚÈÝ

ÔÚ»¯Ñ§ÐËȤС×é»î¶¯ÖУ¬Ð¡É½°ÑÒ»±êÓС°Éúʯ»Ò ¸ÉÔï¼Á¡±µÄСֽ´ü´øµ½Ñ§Ð£½øÐÐʵÑé¡£¸ÉÔï¼ÁÊÇ·ñ±äÖÊ£¿Ð¡É½Éè¼Æ²¢½øÐÐÁËÈçÏÂʵÑ飬ÇëÄã°ïËûÍê³ÉʵÑ鱨¸æ¡£

£¨1£©

 

ʵÑé²½Öè

ʵÑéÏÖÏó

½áÂÛ

¢Ù

 

¸ÉÔï¼ÁÖк¬ÓÐCaO

¢ÚÈ¡ÉÙÁ¿ÓÃÑùÆ·ÖÆµÃ

µÄÈÜÒºÓÚÊÔ¹ÜÖУ¬

µÎÈ뼸µÎ·Ó̪ÊÔÒº

 

¸ÉÔï¼ÁÖк¬ÓÐCa(OH)2

¸ÉÔï¼Á²¿·Ö±äÖÊ

£¨2£©¼ÈÈ»¸ÉÔï¼ÁÖÐÒѺ¬ÓÐCa(OH)2£¬Ð¡É½ÓÖ²ÂÏ뻹¿ÉÄÜÓÐÁíÒ»ÖÖÎïÖÊÉú²ú£¬Ô­ÒòÊÇ      

                  £¨Óû¯Ñ§·½³Ìʽ±íʾ£©¡£ÇëÄãÉè¼ÆÊµÑéÖ¤Ã÷СɽµÄ²ÂÏ루¼òҪд³öʵÑé²½Öè¡¢ÏÖÏó¼°½áÂÛ£©                                                           

                                                                              ¡£

£¨3£©Ð¡Î÷ÈÏΪ²½Öè¢Ú²»ÑÏÃÜ£¬ÀíÓÉÊÇ                                             ¡£

 

¡¾´ð°¸¡¿

£¨1£©

ʵÑé²½Öè

ʵÑéÏÖÏó

½áÂÛ

¢ÙÈ¡ÉÙÁ¿ÑùÆ·ÓÚÊÔ¹ÜÖУ¬¼ÓË®Èܽâ

ÊÔ¹ÜÍâ±Ú·¢ÈÈ

 

 

ÎÞÉ«·Ó̪±äºì

 

£¨2£©CO2 +Ca(OH)2===CaCO3¡ý+ H2O

È¡ÉÙÁ¿¹ÌÌåÓÚÊÔ¹ÜÖУ¬²¢¼ÓÈëÊÊÁ¿Ï¡ÑÎËᣬÈç¹ûÓÐÆøÅݲúÉú£¬Ö¤Ã÷¹ÌÌ庬ÓÐ̼Ëá¸Æ

£¨3£©¢ÙÖÐÑõ»¯¸ÆÈÜÓÚˮҲ»áÉú³ÉÇâÑõ»¯¸Æ£¬Ê¹·Ó̪±äºì

£¨4£©¸ÉÔï¼ÁÖÐÑõ»¯¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ

¡¾½âÎö¡¿£¨1£©ÓÉÓÚÉúʯ»ÒÓöË®»á·ÅÈÈ£¬¶øÇâÑõ»¯¸ÆÈÜÒºÄÜʹÎÞÉ«·Ó̪ÊÔÒº±äºì£»

£¨2£©ÓÉÓÚÇâÑõ»¯¸ÆÄÜºÍ¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸Æ»á½øÒ»²½µÄ±äÖÊ£¬¶øÌ¼Ëá¸ÆÊÇ̼ËáÑοÉÒÔºÍËáÈÜÒº·´Ó¦£»

£¨3£©ÓÉÓÚÇâÑõ»¯¸Æ²»Ò»¶¨ÊDZäÖÊÉú³ÉµÄ£¬Ò²ÓпÉÄÜΪ±äÖʵÄÉúʯ»ÒºÍ¼ÓÈëµÄË®Éú³ÉµÄ£®

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2010?½õÖÝ£©ÔÚ»¯Ñ§ÐËȤС×é»î¶¯ÖУ¬Ò»±êÓС°Éúʯ»Ò¸ÉÔï¼Á¡±µÄСֽ´üÒýÆðÁËͬѧÃǵÄÐËȤ£®ÇëÄãºÍ»¯Ñ§ÐËȤС×éµÄͬѧÃÇÒ»Æðȥ̽¾¿£º
[ʵÑé̽¾¿1]È¡×ãÁ¿ÑùÆ·ÓÚСÉÕ±­ÖУ¬¼ÓÊÊÁ¿Ë®£¬´¥Ãþ±­±Ú£¬ÎÞÈȸУ®¸ù¾ÝÉÏÊöʵÑ飨¼ÙÈçʵÑé¹ý³ÌÖÐÎÞÈÈÁ¿É¢Ê§£©£¬ÄãÈÏΪ´Ë¸ÉÔï¼Á
È«²¿
È«²¿
£¨ÌûÓС±¡°²¿·Ö¡°»ò¡°È«²¿¡°£©±äÖÊ£®
[×ö³ö²ÂÏë]²ÂÏëÒ»£º±äÖʵĸÉÔï¼Á³É·ÖÊÇÇâÑõ»¯¸Æ£®
²ÂÏë¶þ£º±äÖʵĸÉÔï¼Á³É·ÖÊÇ
ÇâÑõ»¯¸ÆºÍ̼Ëá¸Æ
ÇâÑõ»¯¸ÆºÍ̼Ëá¸Æ
£®
²ÂÏëÈý£º±äÖʵĸÉÔï¼Á³É·ÖÊÇ
̼Ëá¸Æ
̼Ëá¸Æ

[²ÂÏëÑéÖ¤]СÄþÉè¼ÆµÄʵÑé·½°¸£ºÈ¡ÊÊÁ¿ÑùÆ·¼ÓÈëÊÔ¹ÜÖУ¬¼ÓË®Õñµ´ºó¾²Öã¬Ï²ãÓв»ÈÜÎÉϲãÇåÒºÖеÎÈë·Ó̪ÈÜÒº£¬ÈÜÒº±äºì£¬Ôò±äÖʵĸÉÔï¼Á³É·ÖÊÇÇâÑõ»¯¸Æ£®Í¬Ñ§ÃǾ­¹ýÈÏÕæÌÖÂÛºóÒ»ÖÂÈÏΪСÄþµÄʵÑé·½°¸²»ºÏÀí£¬ÄãÈÏΪ²»ºÏÀíµÄÀíÓÉÊÇ
ϲãµÄ²»ÈÜÎï¿ÉÄÜÓÐ̼Ëá¸Æ£¬²»ÄÜ˵Ã÷±äÖʵĸÉÔï¼Á³É·ÖÖ»ÓÐÇâÑõ»¯¸Æ
ϲãµÄ²»ÈÜÎï¿ÉÄÜÓÐ̼Ëá¸Æ£¬²»ÄÜ˵Ã÷±äÖʵĸÉÔï¼Á³É·ÖÖ»ÓÐÇâÑõ»¯¸Æ
£®ÇëÄãÔÚ²ÂÏë¶þºÍ²ÂÏëÈýÖÐÑ¡ÔñÈÎÒ»²ÂÏëÉè¼ÆÊµÑé½øÐÐ̽¾¿£¬Íê³ÉÏÂÃæµÄʵÑ鱨¸æ£º
    ÊµÑé²Ù×÷    ÊµÑéÏÖÏó    ÊµÑé½áÂÛ
ÔÚ»¯Ñ§ÐËȤС×é»î¶¯ÖУ¬Ð¡É½°ÑÒ»±êÓС°Éúʯ»Ò ¸ÉÔï¼Á¡±µÄСֽ´ü´øµ½Ñ§Ð£½øÐÐʵÑ飮¸ÉÔï¼ÁÊÇ·ñ±äÖÊ£¿Ð¡É½Éè¼Æ²¢½øÐÐÁËÈçÏÂʵÑ飬ÇëÄã°ïËûÍê³ÉʵÑ鱨¸æ£®
£¨1£©
ʵÑé²½Öè ʵÑéÏÖÏó ½áÂÛ
¢Ù
È¡ÑùÓÚСÊÔ¹ÜÖУ¬¼ÓË®£¬
ÓÃÊÖ´¥ÃþÊÔ¹ÜÍâ±Ú
È¡ÑùÓÚСÊÔ¹ÜÖУ¬¼ÓË®£¬
ÓÃÊÖ´¥ÃþÊÔ¹ÜÍâ±Ú
ÊÔ¹ÜÍâ±Ú·¢ÈÈ
ÊÔ¹ÜÍâ±Ú·¢ÈÈ
¸ÉÔï¼ÁÖк¬ÓÐCaO
¢ÚÈ¡ÉÙÁ¿ÓÃÑùÆ·ÖÆµÃµÄÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎÈ뼸µÎ·Ó̪ÊÔÒº
ÎÞÉ«·Ó̪ÈÜÒº±äºìÉ«
ÎÞÉ«·Ó̪ÈÜÒº±äºìÉ«
¸ÉÔï¼ÁÖк¬ÓÐCa£¨OH£©2
¸ÉÔï¼Á²¿·Ö±äÖÊ
£¨2£©¼ÈÈ»¸ÉÔï¼ÁÖÐÒÑÓÐCa£¨OH£©2£¬Ð¡É½ÓÖ²ÂÏ뻹¿ÉÄÜÓÐÁíÒ»ÖÖÎïÖÊÉú³É£¬Ô­ÒòÊÇ
CO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O
CO2+Ca£¨OH£©2¨TCaCO3¡ý+H2O

£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£®ÇëÄãÉè¼ÆÊµÑéÖ¤Ã÷СɽµÄ²ÂÏ루¼òҪд³öʵÑé²½Öè¡¢ÏÖÏó¼°½áÂÛ£©
È¡ÉÙÁ¿µÄÑùÆ·ÓÚÊÔ¹ÜÖУ¬µÎÈ뼸µÎÏ¡ÑÎËᣬÈôÓÐÆøÅݲúÉú£¬ÔòÓÐ̼Ëá¸Æ
È¡ÉÙÁ¿µÄÑùÆ·ÓÚÊÔ¹ÜÖУ¬µÎÈ뼸µÎÏ¡ÑÎËᣬÈôÓÐÆøÅݲúÉú£¬ÔòÓÐ̼Ëá¸Æ
£®
£¨3£©Ð¡Î÷ÈÏΪ²½Öè¢Ú²»ÑÏÃÜ£¬ÀíÓÉÊÇ
¢ÙÖÐÇâÑõ»¯¸Æ¿ÉÄÜÊÇË®ºÍÑõ»¯¸Æ·´Ó¦¶øÉú³ÉµÄ
¢ÙÖÐÇâÑõ»¯¸Æ¿ÉÄÜÊÇË®ºÍÑõ»¯¸Æ·´Ó¦¶øÉú³ÉµÄ
£®
£¨4£©Óä¿ìµÄС×é»î¶¯½áÊøÁË£¬³ýÒÔÉϲÂÏ뼰ʵÑ飬Ä㻹Ïë¶Ô¸Ã¸ÉÔï¼ÁµÄ³É·Ö½øÐÐÄÄЩ·½ÃæµÄ̽¾¿
¸ÉÔï¼ÁÖÐÑõ»¯¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ
¸ÉÔï¼ÁÖÐÑõ»¯¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ
£¨Ð´³öÒ»Ìõ¼´¿É£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø