ÌâÄ¿ÄÚÈÝ

Ë®ÊÇÈËÀ౦¹óµÄ×ÔÈ»×ÊÔ´£¬¸ù¾ÝË®µÄÏà¹ØÖªÊ¶»Ø´ðÏÂÁÐÎÊÌ⣻

(1)ÈÕ³£Éú»îÖг£ÓÃ______À´Çø·ÖӲˮºÍÈíË®¡£

(2)Éú»îÖг£ÓÃ______·½·¨½µµÍ×ÔÀ´Ë®µÄÓ²¶È¡£

(3)ÔÚÏ´Íëʱ³£¼ÓÈëÏ´µÓ¼Á£¬ÀûÓÃÁËÏ´µÓ¼ÁµÄ______×÷Óá£

(4)µç½âË®µÄ»¯Ñ§·½³ÌʽÊÇ£º_________________________¡£

·ÊÔíË® ¼ÓÈÈÖó·Ð È黯 2H2O2H2¡ü+O2¡ü ¡¾½âÎö¡¿(1)ÈÕ³£Éú»îÖг£Ó÷ÊÔíË®À´Çø·ÖӲˮºÍÈíË®£¬Ó²Ë®ÅÝÄ­¶à£¬ÈíË®ÅÝÄ­ÉÙ¡£(2)Éú»îÖг£ÓüÓÈÈÖó·Ð·½·¨½µµÍ×ÔÀ´Ë®µÄÓ²¶È¡£(3)ÔÚÏ´Íëʱ³£¼ÓÈëÏ´µÓ¼Á£¬ÀûÓÃÁËÏ´µÓ¼ÁµÄÈ黯×÷Óá£(4)µç½âË®µÄ»¯Ñ§·½³ÌʽÊÇ2H2O2H2¡ü+O2¡ü¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ѧϰÁË¡¶º£Ë®¡°ÖƼ¡·Ò»¿Îºó£¬Í¬Ñ§ÃÇÄ£Äâ¡°ºîÊÏÖÆ¼î·¨¡±½øÐÐʵÑ飮

£¨²éÔÄ×ÊÁÏ£©°±Æø(NH3)ÊÇÒ»ÖÖÓд̼¤ÐÔÆøÎ¶µÄÆøÌ壬¼«Ò×ÈÜÓÚË®£¬ÆäË®ÈÜÒºÏÔ¼îÐÔ£®

£¨Ä£ÄâʵÑ飩ÑéÖ¤ºîÊÏÖÆ¼î·¨ÄÜ»ñµÃ´¿¼î

²½Öè

ʵÑé×°ÖÃ

ʵÑé²Ù×÷¼°ÏÖÏó

½âÊÍÓë½áÂÛ

(1)

ÏÈ´Óa¹ÜͨÈë____(Ìî ¡°CO2¡±»ò¡°NH3¡±)£¬Ò»¶Îʱ¼äºó£¬ÔÙ´Ób¹ÜͨÈë___(Ìî¡°CO2¡±»ò¡°NH3¡±)£¬ÈÜÒºÖÐÓйÌÌåÎö³ö

ÕºÓÐÏ¡ÁòËáµÄÃÞ»¨¿ÉÎüÊÕ¹ýÁ¿µÄ°±Æø£¬ÒÔÃâ»Ó·¢µ½¿ÕÆøÖС£

(2)

³ä·Ö¼ÓÈÈ£¬¹Û²ìµ½µÄÏÖÏóÊÇ£ºÊԹܿÚÓÐË®Ö飬ÉÕ±­Öеĵ¼¹Ü¿ÚÓÐÆøÅÝð³ö£¬____¡£

²½Öè1Îö³öµÄ¹ÌÌåÊÇ̼ËáÇâÄÆ

(3)

µÎ¼Ó×ãÁ¿Ï¡ÑÎËᣬÓÐÆøÅݲúÉú£¬¹ÌÌåÖð½¥Ïûʧ

²½Öè2¼ÓÈȺóµÃµ½µÄ¹ÌÌåÊÇ´¿¼î

²½Öè1·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ ______________¡£

£¨ÊµÑ鷴˼£©(1)ͬѧÃÇÈÏΪ²½Öè3µÄʵÑ黹²»×ãÒԵóö¡°²½Öè2¼ÓÈȺóµÃµ½µÄ¹ÌÌåÊÇ´¿¼î¡±µÄ½áÂÛ£¬¾­¹ýÌÖÂÛ£¬´ó¼ÒÒ»ÖÂÈÏΪÐèÒª²¹³äµÄʵÑéÊÇ____________¡£

(2)Ò²ÓÐͬѧÈÏÎªÖÆµÃµÄ´¿¼îÖпÉÄܺ¬ÓÐÂÈ»¯ÄÆÔÓÖÊ£¬ ÓÚÊÇÓÖÉè¼ÆÁËÒÔÏÂʵÑé²¢µÃ³ö½áÂÛ£º

ʵÑé²Ù×÷

ʵÑéÏÖÏó

ʵÑé½áÂÛ

_________

____________

ÖÆµÃµÄ´¿¼îÖк¬ÓÐÂÈ»¯ÄÆ

NH3 CO2 ³ÎÇåʯ»ÒË®±ä»ë×Ç NaCl + H2O + NH3 + CO2 = NaHCO3 + NH4Cl ÏȼÓÈë¹ýÁ¿ÂÈ»¯¸Æ£¬¹Û²ìÊÇ·ñ»ë×Ç£¬È¡³ÎÇåÈÜÒº£¬ÔٵμÓÑÎËá¹Û²ìÊÇ·ñÓÐÆøÅÝ¡£ È¡´¿¼îÑùÆ·ÓÚÊÔ¹ÜÖмÓË®Èܽ⣬¼ÓÈë¹ýÁ¿Ï¡ÏõËᣬºóµÎ¼¸µÎÏõËáÒøÈÜÒº ÏÈÓÐÆøÅݲúÉú£¬ºó²úÉú°×É«³Áµí¡£ ¡¾½âÎö¡¿¡¾Ä£ÄâʵÑé¡¿£¨1£©°±Æø¼«Ò×ÈÜÓÚË®£¬ËùÒÔaÊÔ¹ÜÓ¦¸ÃÌí¼Ó°±Æø£¬bÊÔ¹ÜÌí¼Ó¶þÑõ»¯Ì¼£¬·´Ö®¶þÑõ»¯Ì¼ÎÞ·¨³ä·ÖÈܽâºÍ...

ʵÑę́ÉÏÓÐÒ©Æ·£ºKMnO4¡¢Ê¯»Òʯ¡¢Ï¡ÑÎËá¡¢ÃÞ»¨ºÍ»ð²ñ£¬»¹ÓÐÏÂÁÐÒÇÆ÷(ÊýÄ¿²»ÏÞ)£ºÇë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ÒÇÆ÷¢ÚµÄÃû³Æ___________,ÒÇÆ÷¢ÛµÄÃû³Æ____________.

(2)Çë´ÓÒÔÉÏÒÇÆ÷ÖÐÑ¡³öÄÜÖÆÈ¡¶þÑõ»¯Ì¼µÄ·¢Éú×°ÖúÍÊÕ¼¯×°ÖÃ_____(ÌîÒÇÆ÷ÐòºÅ)£¬¶þÑõ»¯Ì¼µÄÊÕ¼¯·½·¨ÊÇ___________________¡£

(3)ÊÕ¼¯Ò»ËÜÁÏÆ¿¶þÑõ»¯Ì¼ÆøÌ壬ѸËÙ×¢ÈëÊÊÁ¿µÄʯ»ÒË®²¢Ðý½ôÆ¿Èû£¬Õðµ´Æ¿×Ó£¬¿´µ½³ÎÇåʯ»ÒË®±ä______£¬Í¬Ê±¿´µ½Æ¿×Ó±ä±ñ£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________¡£

(4)Èô²¹³äÒ»¸ö²£Á§ÒÇÆ÷______£¬»¹¿ÉÒÔÖÆÈ¡ÑõÆø£¬ÑõÆøµÄ¼ìÑé·½·¨ÊÇ_______________¡£

(5)KMnO4ÊôÓÚÎïÖÊ·ÖÀàÖеÄ______

a.µ¥ÖÊ b. »¯ºÏÎï c. Ñõ»¯Îï d. ÑÎ

×¶ÐÎÆ¿ ³¤¾±Â©¶· ¢Ú¢Û¢Ü¢Þ ÏòÉÏÅÅ¿ÕÆø·¨ »ë×Ç Ca(OH)2+CO2=CaCO3¡ý+ H2O ÊÔ¹Ü ½«´ø»ðÐǵÄľÌõÉìÈë¼¯ÆøÆ¿ÖУ¬ÈôľÌõ¸´È¼£¬Ö¤Ã÷ÊÇÑõÆø bd ¡¾½âÎö¡¿(1)ÒÇÆ÷¢ÚµÄÃû³ÆÊÇ×¶ÐÎÆ¿£¬ÒÇÆ÷¢ÛµÄÃû³ÆÊdz¤¾±Â©¶·¡£(2)ÄÜÖÆÈ¡¶þÑõ»¯Ì¼µÄ·¢Éú×°ÖúÍÊÕ¼¯×°ÖÃÊǢڢۢܢޣ¬¹ÌÌåºÍÒºÌå·´Ó¦²»Ðè¼ÓÈÈÖÆÈ¡ÆøÌ壬¶þÑõ»¯Ì¼ÃÜ¶È±È¿ÕÆø´ó¡£¶þÑõ»¯Ì¼µÄÊÕ¼¯·½·¨ÊÇÏòÉÏÅÅ¿ÕÆø·¨¡£(3)ÊÕ¼¯Ò»ËÜÁÏÆ¿¶þÑõ»¯Ì¼ÆøÌ壬Ѹ...

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø