ÌâÄ¿ÄÚÈÝ
¸ÖÌúÊÇʹÓÃ×î¶àµÄ½ðÊô²ÄÁÏ¡£
(1)ÉúÌúºÍ¸Ö¶¼ÊÇÌúºÏ½ð£¬ÆäÖк¬Ì¼Á¿½Ï¸ßµÄÊÇ_______¡£
(2)ÈËÃdz£Óá°ÍǽÌú±Ú¡±À´ÐÎÈÝÎïÌåµÄ¼á¹Ì£¬µ«ÌúÔÚÒ»¶¨Ìõ¼þÏÂÒ²ÄÜ·¢Éú¸÷ÖÖ·´Ó¦£¬ÈçÌúË¿ÔÚÑõÆøÖÐȼÉÕ£¬Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________¡£
(3)½«m gÑõ»¯Í¼ÓÈëÏ¡ÁòËáÖÐÍêÈ«Èܽâºó£¬ÔÙ¼ÓÈëÌú·Û³ä·Ö·´Ó¦£¬¹ýÂË£¬µÃµ½ÂËÔüAºÍÂËÒºB¡£ÔÙ½«ÂËÔüA¼ÓÈë×ãÁ¿Ï¡ÁòËáÖУ¬ÓÐÆøÅÝð³ö£¬³ä·Ö·´Ó¦ºó£¬Ê£Óà¹ÌÌåÎïÖʵÄÖÊÁ¿Îª12.8 g¡£
¢ÙÂËÔüµÄ³É·ÖÊÇ_______£¬ÂËÒºBµÄ³É·ÖÊÇ
_______¡£
¢ÚÔÑõ»¯ÍµÄÖÊÁ¿m£½_______g¡£
(1)ÉúÌú (2) 3Fe£«2O2
Fe3O4
(3)¢ÙFe¡¢Cu(»òÌú¡¢Í) FeSO4 ¢Ú16¡¡
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿