ÌâÄ¿ÄÚÈÝ
ʯ»ÒʯÊÇÒ»ÖÖÖØÒªµÄ½¨Öþ²ÄÁÏ£®ÏÖ¶ÔijµØÊ¯»ÒʯȡÑù²¢½øÐÐÁËÈçÏµĶ¨Á¿ÊµÑ飮
Çë·ÖÎö¼ÆË㣺
£¨1£©ÊµÑéÖÐÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿
£¨2£©¸Ãʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£¿£¨¼ÙÉèʯ»ÒʯÑùÆ·ÖеÄÔÓÖʲ»ÓëÑÎËá·´Ó¦Ò²²»ÈÜÓÚË®£©
| ʵÑé²½Öè | ¢Ù³ÆÈ¡ÉÕ±µÄÖÊÁ¿ | ¢Ú½«ÊÊÁ¿ÑÎËá¼ÓÈëÉÕ±Öбû³ÆÖØ | ¢Û³ÆÈ¡ÉÙÁ¿Ê¯»ÒÑùÆ·¼ÓÈëÉÕ±ÖУ¬Ê¹Ö®Óë¹ýÁ¿Ï¡ÑÎËá·´Ó¦ | ¢Ü´ý·´Ó¦ÍêÈ«ºó³ÆÁ¿ |
| ʵÑéͼʾ | ||||
| ʵÑéÊý¾Ý | ÉÕ±µÄÖÊÁ¿Îª52.0g | ÉÕ±ºÍÑÎËáµÄÖÊÁ¿Îª102.0g | ʯ»ÒʯµÄÑùÆ·µÄÖÊÁ¿Îª6.0g | ÉÕ±ºÍÆäÖлìºÏÎïµÄÖÊÁ¿Îª105.8g |
£¨1£©ÊµÑéÖÐÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿
£¨2£©¸Ãʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£¿£¨¼ÙÉèʯ»ÒʯÑùÆ·ÖеÄÔÓÖʲ»ÓëÑÎËá·´Ó¦Ò²²»ÈÜÓÚË®£©
¿¼µã£º¸ù¾Ý»¯Ñ§·´Ó¦·½³ÌʽµÄ¼ÆËã
רÌ⣺Óйػ¯Ñ§·½³ÌʽµÄ¼ÆËã
·ÖÎö£º¸ù¾ÝÌâ¸ÉÌṩµÄÊý¾Ý¿ÉÒÔÇó³ö¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬¸ù¾ÝÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬Çó³ö̼Ëá¸ÆµÄÖÊÁ¿´Ó¶øÇó³ö̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£®
½â´ð£º½â£º£¨1£©»¯Ñ§·´Ó¦Ç°ºó£¬¸÷ÎïÖʵÄÖÊÁ¿×ܺͲ»±ä£¬¹ÊÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿=102.0g+6.0g-105.8g=2.2g£»
£¨2£©Éè̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
100 44
x 2.2g
=
x=5g
¹Êʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý=
¡Á100%¡Ö83.3%
´ð£ºÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2g£¬Ê¯»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ83.3%£®
£¨2£©Éè̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
100 44
x 2.2g
| 100 |
| x |
| 44 |
| 2.2g |
¹Êʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý=
| 5g |
| 6g |
´ð£ºÉú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2g£¬Ê¯»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ83.3%£®
µãÆÀ£º±¾Ì⿼²éµÄÊǸù¾Ý»¯Ñ§·½³ÌʽµÄ¼ÆË㣬Íê³É´ËÌ⣬¿ÉÒÔÒÀ¾ÝÒÑÓеÄ֪ʶ½øÐУ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁб仯ÊôÓÚÎïÀí±ä»¯µÄÊÇ£¨¡¡¡¡£©
| A¡¢È¼·ÅÑÌ»¨ | B¡¢Ãæ°ü·¢Ã¹ |
| C¡¢±£ÏÕË¿ÈÛ¶Ï | D¡¢Ã×Äð³É¾Æ |