ÌâÄ¿ÄÚÈÝ

 Ð¡Ã·Í¬Ñ§Ñ§Ï°Á˵¥ÖÊ¡¢Ñõ»¯Îï¡¢Ëá¡¢¼î¡¢ÑÎÐÔÖʺ󣬷¢ÏÖÐí¶à²»Í¬Àà±ðµÄÎïÖÊ·´Ó¦Ê±ÄÜÉú²úÑΣ¬ÓÚÊÇËý¹¹½¨ÁËÏÂͼËùʾµÄÖªÊ¶ÍøÂçͼ¡£Í­¼°Æä»¯ºÏÎïÔÚ¹¤ÒµÉÏÓÐÖØÒªµÄÓ¦Ó᣽èÖúÍøÂçͼ»Ø´ð
(1)д³öÓÃËáºÍ¼îÉú²úÁòËáÍ­µÄ»¯Ñ§·½³Ìʽ£º______________________________¡£
(2)ÇëÄã°ÑͼÖТ٢ڴ¦²¹³äÍêÕû£¬ÒªÇó²»ÄÜÓëͼÖÐÒÑÓÐÐÅÏ¢ÖØ¸´¡£
¢Ù___________£¬¢Ú___________
(3)¸ù¾ÝÍøÂçͼ¿ÉÖÆ±¸ÎïÖÊ¡£ÀýÈ磬ij»ØÊÕº¬Í­µçÀ·ÏÁϵŤ³§ÓÐÏÂÁÐÖÆÍ­µÄ·½°¸
¢Ùд³öÏÂÁв½ÖèÖеĻ¯Ñ§·½³Ìʽ£º
²½Öè¢ó£º__________________________¡£²½ÖèV£º___________________________¡£
¢ÚÉÏÊö·½°¸ÖпÉÄÜÔì³É¿ÕÆøÎÛȾµÄ²½ÖèÊÇ______________________ ¡£   
£¨1£©H2SO4 + Cu(OH)2==CuSO4 + 2H2
£¨2£©Ëá+ÑΣ»½ðÊô+ÑÎ
£¨3£©¢Ù2NaOH+CuSO4== Cu(OH)2¡ý+ Na2SO4£» CO+CuOCO2+Cu£» ¢Ú²½Öè¢ñºÍ²½Öè¢õ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø