ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©A¡¢B¡¢C¡¢D¡¢EΪ³õÖл¯Ñ§³£¼ûÎïÖÊ£¬ËüÃÇÖ®¼äÓÐÈçͼ1ËùʾµÄת»¯¹ØÏµ£¨¡°¡ú¡±±íʾÉú³É£©¡£ÆäÖÐE¿ÉÓÃÓÚ¼ìÑ鯸ÌåB¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©EÎïÖʵĻ¯Ñ§Ê½Îª          ¡£

£¨2£©AÔÚÉú²ú¡¢Éú»îÖÐÓй㷺µÄÓ¦Óã¬ÊÔ¾ÙÒ»Àý˵Ã÷          ¡£

£¨3£©D¡úAµÄ»¯Ñ§·½³ÌʽΪ          ¡£

£¨4£©C¡úDµÄ»¯Ñ§·½³ÌʽΪ          ¡£

£¨5£©ÓÃͼ2ËùʾװÖýøÐÐʵÑ飬ÒÔʵÏÖD¡úEµÄת»¯£¬¹Û²ìµ½UÐ͹Üa¶ËÒºÃæÃ÷ÏÔ½µµÍ£¬²úÉúÕâÒ»ÏÖÏóµÄÔ­ÒòÊÇ          ¡£

 

¡¾´ð°¸¡¿

£¨5·Ö£©Ã¿¿Õ1·Ö£¬ÆäËûºÏÀí´ð°¸µÃ·Ö

£¨1£©Ca£¨OH£©2  £»      £¨2£©¼±¾È²¡ÈË

£¨3£©2H2O2H2¡ü+O2¡ü

£¨4£©CaCO3+2HCl = CaCl 2+CO2¡ü+H2O

£¨5£©CaO+H2O= Ca£¨OH£©2·Å³öÈÈÁ¿£¬Ê¹¼¯ÆøÆ¿ÄÚÆøÌå·Ö×Ó¼ä¿Õ϶±ä´ó£¬´Ó¶øÌå»ýÔö´ó£¬UÐ͹ÜÄÚÒºÃæÏòÓÒÆ«×ª¡£

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø