ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ï±íÊÇǰ18ºÅÔªËØÔÚÖÜÆÚ±íÖеIJ¿·ÖÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©µØ¿ÇÖк¬Á¿×î¶àµÄÔªËØÊÇ______£¨ÌîÔªËØ·ûºÅ£©£¬¸ÃÔªËØÊôÓÚ__________ÔªËØ£¨Ìî¡°½ðÊô¡±»ò¡°·Ç½ðÊô¡±£©¡£

£¨2£©Çëд³öµÚ16ºÅÔªËØµÄÔ­×ӽṹʾÒâͼ__________£¬Ç°18ºÅÔªËØÖÐÐγɻ¯ºÏÎïÖÖÀà×î¶àµÄÔªËØÊÇ____________£¨ÌîÔªËØ·ûºÅ£©¡£

£¨3£©13ºÅÔªËØµÄÑõ»¯ÎïÓëH2SO4·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________£¬

6ºÅÔªËØµÄ×î¸ß¼ÛÑõ»¯ÎïÓë×ãÁ¿NaOH·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________¡£

£¨4£©³ýµÚ1ÖÜÆÚÍ⣬ͬÖÜÆÚÔªËØµÄÔ­×ӽṹµÄÏàͬµãÊÇ__________________¡£

¡¾´ð°¸¡¿ O ·Ç½ðÊô C Al2O3+3H2SO4= Al2(SO4)3+3H2O CO2+2NaOH= Na2CO3+H2O µç×Ó²ãÊýÏàͬ

¡¾½âÎö¡¿£¨1£©µØ¿ÇÖк¬Á¿×î¶àµÄÔªËØÊÇÑõÔªËØ£¬¸ÃÔªËØÊôÓڷǽðÊô£»

£¨2£©¸ù¾ÝÔ­×ӽṹʾÒâͼµÄ»­·¨»­³öÁòÔ­×ӵĽṹʾÒâͼ£»Ðγɻ¯ºÏÎïÖÖÀà×î¶àµÄÔªËØÊÇ̼£»

£¨3£©13ºÅÔªËØÎªÂÁÔªËØ£¬ÂÁµÄÑõ»¯ÎïΪÑõ»¯ÂÁ£¬ÓëÁòËá·´Ó¦Éú³ÉÑκÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºAl2O3+3H2SO4=Al2£¨SO4£©3+3H2O£»6ºÅÔªËØÊÇ̼£¬×î¸ßÑõ»¯ÎïΪCO2£¬Óë×ãÁ¿NaOH·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCO2+2NaOH=Na2CO3+H2O£»

£¨4£©ÓÉÌâ¸Éͼ±í¿ÉÖª£¬Í¬Ò»ÖÜÆÚÔªËØÔ­×ӽṹµÄ¹æÂÉÊÇÔ­×ÓµÄ×îÍâ²ãµç×ÓÊý´Ó1ÒÀ´ÎµÝÔöµ½8£¬µç×Ó²ãÊýÏàͬ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø