ÌâÄ¿ÄÚÈÝ
СÐÃͬѧÉè¼ÆÈçÏÂʵÑé×°Öã¨Ìú¼Ų̈µÈÒÇÆ÷Ê¡ÂÔ£©ÖƱ¸CO2ºÍÑéÖ¤CO2ÄÜÓëNaOH·´Ó¦¡£
£¨1£©×°ÖÃBµÄ×÷ÓÃÊÇ______
£¨2£©Çë²¹³ä»³ö×°ÖÃCÖÐa¡¢bµ¼Æø¹Ü
£¨3£©Ð¡Òâ·ÖÎöʵÑéºó£¬·¢ÏÖ´Ë×°ÖÃÓÐÃ÷ÏÔ²»×㣬ÖÁÉÙÓ¦Ìí¼ÓÒ»ºóÙþÆøÆ¿F£¬ÄãÈÏΪӦ¸ÃÔÚ_____(Ìî×°ÖñàºÅ)Ö®¼ä¼ÓÈë×°ÓÐ______(ÌîÊÔ¼Á±àºÅ)Ï´ÆøÆ¿F¡£
a£®Å¨NaOHÈÜÒº b£®³ÎÇåʯ»ÒË® c£® ±¥ºÍNaHCO3ÈÜÒº d£®±¥ºÍNa2CO3ÈÜÒº
£¨4£©´ò¿ªÖ¹Ë®¼ÐK1£¬¼ì²éÆøÃÜÐÔ£¬¼ÓÈëÒ©Æ·¿ªÊ¼ÊµÑ飬µ±¹Û²ìÖÁ×°ÖÃEµÄÏÖÏóÊÇ__________________________£¬¿ÉÈ·¶¨×°ÖÃCÊÕ¼¯ÂúCO2
£¨5£©µ±×°ÖÃCÖÐÊÕ¼¯ÂúCO2£¬¹Ø±Õֹˮ¼ÐK2£¬°Ñ×¢ÉäÆ÷DÖеÄ5mLŨµÄÇâÑõ»¯ÄÆÑ¹Èëµ½×°ÖÃCÖУ¬»¯Ñ§·½³ÌʽΪ________________________________________,¹Û²ìµ½µÄÏÖÏóÊÇ________________________________________________________.
(6)СƽͬѧÈÏΪ֤Ã÷CO2Óë NaOH·´Ó¦£¬»¹Ó¦°Ñ×¢ÉäÆ÷ÄÚDÖÐŨNaOHÈÜÒº»»³É________,ÔÙ×öÒ»´ÎʵÑ飬ÆäÄ¿µÄÊÇ__________________________¡£
(1)¸ÉÔï¶þÑõ»¯Ì¼ÆøÌå £¨2£©Í¼ÂÔ£¨bÑÓ³¤½Ó½ü¼¯ÆøÆ¿µ×²¿£©
£¨3£©A¡¢B£»c
£¨4£©×ÏɫʯÈïÈÜÒº±äºì £¨5£©2NaOH+CO2=Na2CO3+H2O ×°ÖÃEÖкìɫʯÈïÈÜÒº»áµ¹ÎüÈë×°ÖÃCÖÐ
£¨5£©5mLË® ¶ÔÕÕʵÑé
СÐÃͬѧÉè¼ÆÈçÏÂʵÑé×°Öã¨Ìú¼Ų̈µÈÒÇÆ÷Ê¡ÂÔ£©ÖƱ¸CO2ºÍÑéÖ¤CO2ÄÜÓëNaOH·´Ó¦¡£
![]()
£¨1£©×°ÖÃBµÄ×÷ÓÃÊÇ______
£¨2£©Çë²¹³ä»³ö×°ÖÃCÖÐa¡¢bµ¼Æø¹Ü
£¨3£©Ð¡Òâ·ÖÎöʵÑéºó£¬·¢ÏÖ´Ë×°ÖÃÓÐÃ÷ÏÔ²»×㣬ÖÁÉÙÓ¦Ìí¼ÓÒ»ºóÙþÆøÆ¿F£¬ÄãÈÏΪӦ¸ÃÔÚ_____(Ìî×°ÖñàºÅ)Ö®¼ä¼ÓÈë×°ÓÐ______(ÌîÊÔ¼Á±àºÅ)Ï´ÆøÆ¿F¡£
| A£®Å¨NaOHÈÜÒº | B£®³ÎÇåʯ»ÒË® | C£®±¥ºÍNaHCO3ÈÜÒº | D£®±¥ºÍNa2CO3ÈÜÒº |
£¨4£©´ò¿ªÖ¹Ë®¼ÐK1£¬¼ì²éÆøÃÜÐÔ£¬¼ÓÈëÒ©Æ·¿ªÊ¼ÊµÑ飬µ±¹Û²ìÖÁ×°ÖÃEµÄÏÖÏóÊÇ__________________________£¬¿ÉÈ·¶¨×°ÖÃCÊÕ¼¯ÂúCO2
£¨5£©µ±×°ÖÃCÖÐÊÕ¼¯ÂúCO2£¬¹Ø±Õֹˮ¼ÐK2£¬°Ñ×¢ÉäÆ÷DÖеÄ5mLŨµÄÇâÑõ»¯ÄÆÑ¹Èëµ½×°ÖÃCÖУ¬»¯Ñ§·½³ÌʽΪ_______________________________________,¹Û²ìµ½µÄÏÖÏóÊÇ____________________________________.
(6)СƽͬѧÈÏΪ֤Ã÷CO2Óë NaOH·´Ó¦£¬»¹Ó¦°Ñ×¢ÉäÆ÷ÄÚDÖÐŨNaOHÈÜÒº»»³É________,ÔÙ×öÒ»´ÎʵÑ飬ÆäÄ¿µÄÊÇ__________________________¡£