ÌâÄ¿ÄÚÈÝ

ÒÑ֪ij´¿¼îÊÔÑùÖк¬ÓÐÔÓÖÊÂÈ»¯ÄÆ£¬Îª²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬¿ÉÓÃÏÂͼװÖýøÐÐʵÑé¡£Ö÷Òª²½ÖèÈçÏ£¬ÇëÌî¿Õ£º

¢Ù°´Í¼×é×°ÒÇÆ÷£¬²¢¼ì²é__________________£»
¢Ú½«10gÊÔÑù·ÅÈë×¶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣬µÃµ½ÊÔÑùÈÜÒº£»
¢Û³ÆÁ¿Ê¢Óмîʯ»ÒµÄUÐιܵÄÖÊÁ¿Îª300g£»
¢Ü´Ó·ÖҺ©¶·ÖеÎÈë20%µÄÏ¡ÁòËᣬֱµ½_________Ϊֹ£¬Ð´³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________________£»
¢Ý´Óµ¼¹ÜA´¦»º»º¹ÄÈëÒ»¶¨Á¿µÄ¿ÕÆø£»
¢ÞÔٴγÆÁ¿Ê¢Óмîʯ»ÒµÄUÐιܵÄÖÊÁ¿£»
¢ßÖØ¸´¢ÝºÍ¢ÞµÄ²Ù×÷£¬Ö±µ½UÐιܵÄÖÊÁ¿»ù±¾²»±ä£¬²âµÃÖÊÁ¿Îª303.3g¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖÃÖÐŨÁòËáµÄ×÷ÓÃÊÇ___________________________________¡£
£¨2£©²½Öè¢ÝµÄÄ¿µÄÊÇ_________________________________________¡£
£¨3£©ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊýΪ_________________________________¡£
£¨4£©·ÖҺ©¶·ÖеÄÏ¡H2SO4²»ÄÜ»»³ÉŨÑÎËᣬÀíÓÉÊÇ______________________________¡£
£¨5£©ÈôÓÃÉú³É³ÁµíµÄ·½·¨À´²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬Ó¦Ñ¡ÓõÄÊÔ¼ÁÊÇ____________¡£
¢Ù×°ÖÃµÄÆøÃÜÐÔ
¢Ü²»ÔÙ²úÉúÆøÌ壻Na2CO3+H2SO4==Na2SO4+CO2¡ü+H2O
£¨1£©³ýȥˮ
£¨2£©Ê¹·´Ó¦²úÉúµÄCO2È«²¿µ¼ÈëUÐιÜ
£¨3£©79.5%
£¨4£©Å¨ÑÎËáÓлӷ¢ÐÔ£¬¶Ô²â¶¨ÓÐÓ°Ïì
£¨5£©CaCl2
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Çë´ÓÒÔÏÂI¡¢IIÁ½µÀÌâÖÐÈÎѡһµÀÍê³É£º
I£®ÏÖÓÐÂÈ»¯ÄƺÍ̼ËáÄÆµÄ»ìºÏÎï20¿Ë£¬ÎªÁ˳ýµôÆäÖеÄ̼ËáÄÆ£¬µÃµ½´¿¾»µÄÂÈ»¯ÄÆÈÜÒº£¬Ð¡Ã÷ͬѧ½«¸Ã»ìºÏÎï·ÅÈëÒ»¶¨Á¿µÄË®ÖÐÅäÖÆ³É60¿ËÈÜÒº£¬ÔÙÏòÆäÖмÓÈë50¿ËÂÈ»¯¸ÆÈÜÒº£¬Ç¡ºÃÍêÈ«·´Ó¦£¬Éú³ÉÁ˰×É«³Áµí£¬¹ýÂ˺óµÃµ½100¿ËÈÜÒº£®
£¨1£©ÇóËùµÃÂÈ»¯ÄÆÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£º£¨ÒªÇóд³ö¼ÆËã¹ý³Ì£©£®
£¨2£©Ð¡Ã÷ͬѧµÄ·½°¸ÖÐÂÈ»¯¸ÆÈÜÒººÜÈÝÒ×¹ýÁ¿¶øÒýÈëеÄÔÓÖÊ£¬ÄãÌá³öµÄ¼ÈÄܳýȥ̼ËáÄÆÔÓÖÊ£¬ÓÖÄÜÓÐЧµØ·ÀÖ¹ÐÂÔÓÖÊÒýÈëµÄз½°¸ÊÇ£º
 
£®
II£®ÒÑ֪ij´¿¼îÊÔÑùÖк¬ÓÐÂÈ»¯ÄÆ£¬Îª²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬¿ÉÓÃÏÂͼװÖýøÐÐʵÑ飮£¨ÒÑ֪װÖÃAÖÐÊÔ¼ÁXΪÇâÑõ»¯ÄÆÈÜÒº£¬¼îʯ»ÒΪÇâÑõ»¯ÄÆÓëÑõ»¯¸Æ¹ÌÌåµÄ»ìºÏÎ
¾«Ó¢¼Ò½ÌÍø
Ö÷Òª²½ÖèÈçÏ£º¢Ù°´Í¼×é×°ÒÇÆ÷£¬²¢¼ì²é×°ÖÃÆøÃÜÐÔ£»¢Ú׼ȷ³ÆµÃ6.0g´¿¼îÊÔÑù·ÅÈë×°ÖÃBµÄ¹ã¿ÚÆ¿ÖУº
¢Û´ÓAÖе¼¹Ü»º»ºÍ¨Èë¿ÕÆøÒ»¶Îʱ¼äºó£¬¹Ø±Õµ¯»É¼Ð£»¢Ü³ÆµÃÊ¢Óмîʯ»ÒµÄ¸ÉÔï¹ÜDµÄÖÊÁ¿Îª183.4g£»
¢Ý´Ó·ÖҺ©¶·ÖеÎÈë98gÏ¡ÁòËáÊ±ÆøÅݲ»ÔÙ²úÉú£º¢Þ´ò¿ªµ¯»É¼Ð£¬ÔÙ´ÓAÖе¼¹Ü»ºÂýͨÈë¿ÕÆøÒ»¶Îʱ¼ä£»
¢ßÔٴγÆÁ¿¸ÉÔï¹ÜDµÄ×ÜÖÊÁ¿Îª185.6g£®
£¨1£©ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨ÒªÇóд³ö¼ÆËã¹ý³Ì£©£®
£¨2£©ÎªÁ˼õСÎó²î£¬²½Öè¢ÛºÍ¢ÞÖж¼Í¨ÈëÁËÒ»¶Îʱ¼äµÄ¿ÕÆø£¬Çë¾ÍÆäÖÐÒ»´¦Ì¸Ì¸ÈôÊ¡ÂԸò½Öèºó¶Ô²âÁ¿½á¹ûÔì³ÉµÄÓ°Ïì
 
£®
£¨2011?ÇàÆÖÇø¶þÄ££©ÒÑ֪ij´¿¼îÊÔÑùÖк¬ÓÐÔÓÖÊÂÈ»¯ÄÆ£¬ÎªÁ˲ⶨÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬¿ÉÓÃÈçͼװÖýøÐÐʵÑ飮£¨Å¨ÁòËá¾ßÓиÉÔê×÷Óã©

Ö÷Òª²½ÖèÈçÏ£¬ÇëÌî¿Õ£º
¢Ù°´Í¼×é×°ÒÇÆ÷£¬²¢¼ì²é
×°ÖÃµÄÆøÃÜÐÔ
×°ÖÃµÄÆøÃÜÐÔ
£º
¢Ú½«10gÊÔÑù·ÅÈë×¶ÐÎÆ¿ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣬µÃµ½ÊÔÑùÈÜÒº£»
¢Û³ÆÁ¿Ê¢Óмîʯ»ÒµÄUÐ͹ÜΪ300g£»
¢Ü´Ó·ÖҺ©¶·ÖеÎÈë20%µÄÏ¡ÁòËᣬֱµ½
²»ÔÙ²úÉúÆøÌå
²»ÔÙ²úÉúÆøÌå
Ϊֹ£¬
д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
Na2CO3+H2SO4¨TNa2SO4+H2O+CO2¡ü£®
Na2CO3+H2SO4¨TNa2SO4+H2O+CO2¡ü£®
£»
¢Ý´Óµ¼¹ÜA´¦»º»º¹ÄÈëÒ»¶¨Á¿µÄ¿ÕÆø£»
¢ÞÔٴγÆÁ¿Ê¢Óмîʯ»ÒµÄUÐ͹ܵÄÖÊÁ¿£»
¢ßÖØ¸´¢ÝºÍ¢ÞµÄ²Ù×÷£¬Ö±µ½UÐ͹ܵÄÖÊÁ¿»ù±¾²»±ä£¬³ÆµÃÖÊÁ¿Îª303.3g£®
»Ø´ðÏÂÁÐÎÊÌ⣻
£¨1£©ÊÔÑùÖд¿¼îÓë20%µÄÏ¡ÁòËá·´Ó¦ÖÆµÃ¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊÇ£º
3.3
3.3
g£®
£¨2£©²½Öè¢ÝµÄÄ¿µÄÊÇ£º
ʹ·´Ó¦²úÉúµÄCO2È«²¿µ¼ÈëUÐ͹Ü
ʹ·´Ó¦²úÉúµÄCO2È«²¿µ¼ÈëUÐ͹Ü
£®
£¨3£©Õû¸ö×°ÖÃÖмîʯ»Ò²»Í¬µÄ×÷ÓÃÊÇ£º
BÖÐÎüÊÕ·´Ó¦Éú³ÉµÄCO2£¬CÖзÀÖ¹¿ÕÆøÖÐCO2µÄ¸ÉÈÅ
BÖÐÎüÊÕ·´Ó¦Éú³ÉµÄCO2£¬CÖзÀÖ¹¿ÕÆøÖÐCO2µÄ¸ÉÈÅ
£®
£¨4£©·ÖҺ©¶·ÖеÄÏ¡ÁòËá²»ÄÜ»»³ÉŨÑÎËᣬÀíÓÉÊÇ£º
ŨÑÎËá¾ßÓлӷ¢ÐÔ£¬¶Ô²â¶¨ÓÐÓ°Ïì
ŨÑÎËá¾ßÓлӷ¢ÐÔ£¬¶Ô²â¶¨ÓÐÓ°Ïì
£®
£¨5£©ÈôÓóÁµíµÄ·½·¨À´²â¶¨ÊÔÑùÖеÄÖÊÁ¿·ÖÊý£¬Ó¦Ñ¡ÓõÄÊÔ¼ÁÊÇ£º
CaCl2
CaCl2
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø