ÌâÄ¿ÄÚÈÝ
¢ÙÎÞɫ͸Ã÷ÒºÌ壬Óз¼ÏãÆøÎ¶¢ÚÈÛµã13.2¡æ£¬·Ðµã138.5¡æ
¢ÛÃܶÈ0.86g/cm3¢Ü¿Éȼ¢ÝÓлӷ¢ÐÔ£¬µ«±ÈÆûÓ͵Í
¢ÞÓö»ð¿É±¬Õ¨£¬µ«±¬Õ¨ÐÔ±ÈÆûÓ͵͢ߵͶ¾£¬¶¾ÐÔÓëÆûÓÍÏ൱
£¨1£©ÉϱíÖÐÊôÓÚPXÎïÀíÐÔÖʵÄÊÇ£¨ÌîÐÔÖÊ´úºÅ£©
£¨2£©ÊÔд³öPXÔÚ¿ÕÆøÖÐÍêȫȼÉÕ·´Ó¦µÄ»¯Ñ§·½³Ìʽ
£¨3£©¸ù¾ÝPXµÄÐÔÖÊ£¬´Ó·ÀÖ¹»·¾³ÎÛȾºÍ°²È«µÄ½Ç¶È£¬Ó¦ÈçºÎ±£´æºÍ´¢ÔËPX
¿¼µã£º»¯Ñ§ÐÔÖÊÓëÎïÀíÐÔÖʵIJî±ð¼°Ó¦ÓÃ,Êéд»¯Ñ§·½³Ìʽ¡¢ÎÄ×Ö±í´ïʽ¡¢µçÀë·½³Ìʽ
רÌ⣺½áºÏ¿Î±¾ÖªÊ¶µÄÐÅÏ¢
·ÖÎö£º£¨1£©²»ÐèҪͨ¹ý»¯Ñ§±ä»¯±íÏÖ³öÀ´µÄÐÔÖÊÊôÓÚÎïÖʵÄÎïÀíÐÔÖÊ£»
£¨2£©Êéд»¯Ñ§·½³ÌʽҪעÒâ¹æ·¶ÐÔ£»
£¨3£©¸ù¾ÝÎïÖʵÄÐÔÖÊ¿ÉÒÔÅжÏÎïÖʶԻ·¾³µÄΣº¦³Ì¶È¡¢°²È«ÏµÊý¼°Æä´æÔË·½·¨£®
£¨2£©Êéд»¯Ñ§·½³ÌʽҪעÒâ¹æ·¶ÐÔ£»
£¨3£©¸ù¾ÝÎïÖʵÄÐÔÖÊ¿ÉÒÔÅжÏÎïÖʶԻ·¾³µÄΣº¦³Ì¶È¡¢°²È«ÏµÊý¼°Æä´æÔË·½·¨£®
½â´ð£º½â£º£¨1£©PXµÄÑÕÉ«¡¢×´Ì¬¡¢È۵㡢·Ðµã¡¢Ãܶȡ¢ÆøÎ¶¡¢»Ó·¢ÐÔµÈÐÔÖʲ»ÐèҪͨ¹ý»¯Ñ§±ä»¯±íÏÖ³öÀ´£¬ÊôÓÚÎïÀíÐÔÖÊ£®
£¨2£©PXÔÚ¿ÕÆøÖÐÍêȫȼÉÕÄܹ»Éú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2C8H10+21O2
16CO2+10H2O£®
£¨3£©¸ù¾ÝPXµÄÐÔÖÊ¿ÉÖª£¬ËüÓж¾£¬¾ßÓлӷ¢ÐÔ£¬Óö»ð¿ÉÒÔ±¬Õ¨£¬ËùÒÔÓ¦¸ÃÃÜ·â±£´æ£¬ÑϽûÑÌ»ð£®
¹ÊÌ£¨1£©¢Ù¢Ú¢Û¢Ý£»£¨2£©2C8H10+21O2
16CO2+10H2O£»£¨3£©ÃÜ·â±£´æ¡¢ÑϽûÑÌ»ð£®
£¨2£©PXÔÚ¿ÕÆøÖÐÍêȫȼÉÕÄܹ»Éú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2C8H10+21O2
| ||
£¨3£©¸ù¾ÝPXµÄÐÔÖÊ¿ÉÖª£¬ËüÓж¾£¬¾ßÓлӷ¢ÐÔ£¬Óö»ð¿ÉÒÔ±¬Õ¨£¬ËùÒÔÓ¦¸ÃÃÜ·â±£´æ£¬ÑϽûÑÌ»ð£®
¹ÊÌ£¨1£©¢Ù¢Ú¢Û¢Ý£»£¨2£©2C8H10+21O2
| ||
µãÆÀ£º±¾Ì⿼²éÁËÉç»á·¢Õ¹¹ý³ÌÖУ¬»¯Ñ§ÎïÖÊÔÚÆäÖаçÑݵĽÇÉ«£¬´Ó×ÜÌåÉÏ¿´£¬»¯Ñ§ÎïÖÊÔÚÉç»á·¢Õ¹ÖÐÆðµ½ÁËÖØÒªµÄ×÷Ó㬵«ÊÇÒ²´øÀ´ÁËһϵÁл·¾³ÎÛȾ·½ÃæµÄÎÊÌ⣬Ҫ¿Í¹ÛµØ·ÖÎö»¯Ñ§ÎïÖʵÄ×÷Ó㬼ÈÒªÖØÊÓËüµÄ×÷Óã¬Ò²ÒªÏë·¨Ïû³ýËüµÄ²»ÀûÓ°Ï죮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
| A¡¢¼¯ÆøÆ¿ÖÐµÄÆøÌå¿ÉÄÜÊǶþÑõ»¯Ì¼ |
| B¡¢¼¯ÆøÆ¿ÖÐµÄÆøÌå¿ÉÄÜÊÇ¿ÕÆø |
| C¡¢¼¯ÆøÆ¿ÖÐµÄÆøÌåÒ»¶¨ÊÇÑõÆø |
| D¡¢¼¯ÆøÆ¿ÖÐµÄÆøÌåÒ»¶¨ÊǵªÆø |